Brown eye gene = B
Blue eye gene = b
Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb.
If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes.
If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
A simple way to demonstrate the possibilities of the eye color of the offspring is to divide the potential outcomes into four categories, pairing two chromosomes into each. The outcome is three to one that the child will have brown eyes.
Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
Yes, two parents with brown eyes can have a child with blue eyes if both parents carry a recessive blue eye gene. Blue eyes are a recessive trait, so both parents must carry at least one copy of the blue eye gene for it to be expressed in their child.
well it depends on if the mother has one trait for blue eyes or not. if the mother does then there is a 1/4 chance that the child will have blue eyes and a 3/4 chance that the child will have brown eyes but if the mother does not have a blue eyed gene and she carries 2 genes for brown eyes then your child is going to have brown eyes. but no matter wat color your child's eyes are he/she will carry one gene for blue eyes and will have a possibility to pass down blue eyes to his/her child
In most depictions, Tails has blue eyes.
If both parents are heterozygous for brown eyes (Bb), the possible allele combinations for their children can be represented in a Punnett square: BB, Bb, Bb, and bb. This means there is a 1 in 4 chance, or a 25% probability, that their child will inherit the blue eye genotype (bb) and therefore have blue eyes.
Eye color is actually not controlled by straight Mendellian genetics. However, based on your question, the probability of a brown eyed child would be 50% and the probability of a blue eyed child would be 50%.
Because a parent or grandparent had blue eyes.
The probability of having a blue-eyed child depends on the genetic makeup of the parents. If both parents carry the recessive allele for blue eyes (Bb), where "B" represents the brown eye allele and "b" represents the blue eye allele, there is a 25% chance of having a blue-eyed child (bb). If one or both parents have brown eyes but carry the blue eye allele, the probability may vary. If neither parent has the blue eye allele, the probability of having a blue-eyed child is 0%.
If you have blue eyes and the other parent has blue eyes then all you children will have blue eyes. Blue eyes are a recessive gene and two recessive genes will dominate.
No.
The probability of rolling snake eyes on any one throw is 1 in 36. The probability of NOT rolling a snake eyes is 35 in 36. The only outcome here which we do not desire is that in which a non-snake eye roll occurs four times in a row, therefore, we take (35/36)^4 to find the probability of NEVER getting a snake eyes, and then subtract that answer from 1 to get the chances for any outcome WITH at least one pair of snake eyes. The chances are 10.66% of getting at least one snake eyes in four rolls.
There's a 50% of chance that the children's eyes will be brown.
Blue eyes being recessive just means that someone must have 2 blue-eye genes to have blue eyes. If they had one brown-eye gene and one blue-eye gene, they would have brown eyes but their kid(s) might have blue eyes, depending on the genetics of the other parent.
Mostly brown, as blue eyes is recessive trait. So unless both have blue eyes it is very difficult to see.
Brown color of eye is dominant over blue color. If the mother is homozygous for brown color of eye, than the all the children will have brown color eyes. If mother is heterozygous for brown eyes, than 50% of children will have brown eyes and 50% will have blue eyes.
She had a reddish tented hair with bright blue eyes. All of the Romanov children had blue eyes.