It depends on the parents' genes. If both parent have a Pp genotype, then the offspring has a 25% chance of having a PP genotype. But if both parents have a PP genotype then its 100%.
Tt
Let us assume that both Rr and rr produce red flowers and only rr produces white flowers. Since one parents and the offspring are white, they have rr as genotypes. In order to achieve this result, the other parent would have to haev at least one r in its genotype. Since the otehr parent is red and needs to have one r, it's genotype is Rr. In short, the parents's genotypes are Rr for the red one and rr for the white one.
Pp Not Pp it is pp
The Hardy-Weinberg Equilibrium equation: p2 + 2pq + q2 = 1 p is frequency of dominant allele A q is frequency of recessive allele a p + q always equals 1 pp or p2 is probability of AA occurring qq or q2 is probability of AA occurring 2pq is probability of Aa occurring (pq is probability of Aa, qp is probability of aA, so 2pq is probability of all heterozygotes Aa) These add up to 1 because they represent all possibilities. The frequency of the homozygous recessive genotype
The answer is all of the produced flowers would be Pp
half white and half purple
Pp x Pp yields PP, Pp, Pp, pp. PP is the only genotype which will cause the phenotypic expression of the gene - symptoms of PKU. Therefore the probability is 1/4 or 25%
pp
PP
Tt
Let us assume that both Rr and rr produce red flowers and only rr produces white flowers. Since one parents and the offspring are white, they have rr as genotypes. In order to achieve this result, the other parent would have to haev at least one r in its genotype. Since the otehr parent is red and needs to have one r, it's genotype is Rr. In short, the parents's genotypes are Rr for the red one and rr for the white one.
Pp Not Pp it is pp
because they all have at least one dominant alleles.
The principle of dominance.The gene for purple flowers is dominant, while the gene for white flowers is recessive. We know this because both flowers are homozygous, meaning their genes are the same. The genotype of Penelope (the purple flower) is PP, or purple purple. The genotype of Walter (the white flower) is pp, or white white. Because of this, if the gene for white petals was dominant, all the flower offspring would display white petals. If the genes were codominant, the flower offspring would be lavender, an even mix between the white and purple phenotypes.The Punnet square for this example (if you are a visual person) looks like this:......................Walter........................p | p....................___ | ___................P | Pp | Pp |Penelope .....________................P | Pp | Pp |...................|___|___ |You can clearly see that all the offspring are heterozygous, yet because they all share Penelope's phenotype, it is quite obvious that, again, the gene for purple flowers is dominant.
Pp
The Hardy-Weinberg Equilibrium equation: p2 + 2pq + q2 = 1 p is frequency of dominant allele A q is frequency of recessive allele a p + q always equals 1 pp or p2 is probability of AA occurring qq or q2 is probability of AA occurring 2pq is probability of Aa occurring (pq is probability of Aa, qp is probability of aA, so 2pq is probability of all heterozygotes Aa) These add up to 1 because they represent all possibilities. The frequency of the homozygous recessive genotype
The genotype for a purple plant would be 'PP.' This will depend on whether both parents showed that phenotype, but purple is generally dominant.