KE = 1/2mass * velocity squared
some conversion needed
60 kilometer per hour (1000 meters/1 kg)(1 hr/3600 seconds)
= 17 meter per second
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KE = 1/2(1000 kilograms)(17 m/s)2
= 1.4 X 105 Joules
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Here is what you have to do.
* Convert all units to standard units. In this case, you must convert energy to joules.
* Copy the formula for kinetic energy.
* In this formula, replace all the information you know (in this case, the mass).
* Solve for velocity. The answer, in this case, will be in m/s.
It is 20 m/s.
The velocity is 29.7m/s
50000 Joules
20m/s
1j , 2kj , 200kj , 100j , 20j , 10000,
Efficiency = (Useful Work done)/(Total Work done).This is usually expressed as a percentage.Example:For every 200KJ of energy released from coal in a power plant, only 60KJ is converted to electrical energy. Therefore, Efficiency = 60/200 =30%.
Out of the 200KJ input, 150KJ isn't usable. The only usable output of themachine is the remaining 50KJ.The efficiency of that machine is 50KJ/200KJ = 25% .It must be pointed out, though, that it all depends on your definition of what isusable and non-usable output. For example, if this machine were labeled as an"Office Space Heater", then the 150KJ of heat would be the usable output, andthe efficiency would have been 75% .