What is the velocity of a 60 kg jogger with a kinetic energy of 1080J?

Answer 1

KE = 1/2mass * velocity squared

KE = 1/2mV^2

750 Joules = 1/2(60 kg)V^2

multiply through by 2

1500 = (60 kg)V^2

divide both sides by 60

25 = V^2

take square root of both sides

5 meters/second = velocity

5 m/s (1 mile/1609 meters)(3600 seconds/1 hour)

11.2 miles per hour ( if you needed that )

Answer 2

KE =1/2mV^2

1053.0 J =1/2(69.8 kg)V^2

multiply through by 2

2106 = 69.8V^2

30.1719 = V^2

take square root each side

5.49 m/s = velocity

----------------------

Answer 3

KE = 1/2m∙v2, where m is mass in kg, and v is velocity in m/s. To solve for velocity, do the following:

KE = 1080J = 1080kg∙m2/s2

m = 60kg

v = ?

1080kg∙m2/s2 = 60kg∙v2

v2 = (1080kg∙m2/s2) x 2/60kg = 36m2/s2

√v2 = √36m2/s2 = 6m/s

Answer 4

Kinetic Energy = 1/2 mass X velocity2

rearranging this gives us: velocity = (2KE/mass)^(1/2)

In the case of your question, the velocity is 5.555 m/s

Answer 5

is it 50,5

Answer 6

6m/s