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Your tank is a cylinder with hemispherical end caps. Although you said "cylindrical midsection," we will interpret that to mean the height, h, of the cylinder, which is six feet. We also infer that the radius of the sphere is equal to the radius of the cylinder, which must be the case if the tank has hemispherical end caps. So, the volume of the tank is equal to the sum of the volumes of the two hemispheres and the cylinder.

The equation for the volume of a cylinder is V = pi*r2*h. If you put the two hemispheres together, you have a sphere whose volume is V = (4/3)*pi*r3.

So, V = (4/3)*pi*r3 + pi*r2*h = pi*r2*(4r/3 + h),where h = 6 in this case.

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Q: What is the volume of a cylindrical gas tank that has hemispherical end caps with radius 'r' and whose cylindrical midsection -- not counting the end caps -- is six feet long?
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