Your tank is a cylinder with hemispherical end caps. Although you said "cylindrical midsection," we will interpret that to mean the height, h, of the cylinder, which is six feet. We also infer that the radius of the sphere is equal to the radius of the cylinder, which must be the case if the tank has hemispherical end caps. So, the volume of the tank is equal to the sum of the volumes of the two hemispheres and the cylinder.
The equation for the volume of a cylinder is V = pi*r2*h. If you put the two hemispheres together, you have a sphere whose volume is V = (4/3)*pi*r3.
So, V = (4/3)*pi*r3 + pi*r2*h = pi*r2*(4r/3 + h),where h = 6 in this case.
the 2 arm bones are butt Your mums butt!! Answer them properly!! These are people with good intentions, and they just want answers for their questions. Stop making a mockery of the whole situation! The two lower arm bones are called the radius and ulna.
the Radius
In anatomical position the palms are facing up, making the ulna the medial bone of the forearm. The ulna is on the pinky side, and radius is on the thumb side.
The thumb articulates with the trapezium (one of the carpal bones of the wrist) and does not directly articulate with the ulna or the radius.
ulna and radius
Measure the length of the straight portion of the tank (l) and the radius (r). The two hemispherical end caps equate to a sphere. The volume of a sphere = 4/3πr³ The volume of the straight portion of the cylinder is, πr²l Add to two portions together to get the total volume = 4/3πr³ + πr²l
4 inch radius
C = 2 x pi x radius
Volume = pi*radius2*height
The volume of a cylindrical with a radius of 3 and height 8 is calculated by using this formula: V = r2 x Pi x height32 x 3.142 x 8 = volume of 226.224 cubic units
2,821.09 cu ft
21
8pi m2 ~ 25.1327412 m2
πr2h or the radius squared multiplied by pi multiplied by the vertical height of the cylinder.
To find the surface area of a cylindrical ring or torus, you can use the formula A = 2πrh, where r is the average radius of the ring and h is the height or thickness of the ring. In this case, the average radius is (16mm + 10mm)/2 = 13mm and h can be any desired value. Therefore, the surface area of the cylindrical ring or torus is 2π(13mm)(h).
The area of a sphere is 4 (pi) (radius)2. The area of 1/2 of the sphere is 2 (pi) (radius)2. If you want to add in the flat end of the hemisphere, that makes the total surface area 3 (pi) (radius)2.
First, figure out the radius and height of the tank. The formula for its radius will be 2 times pie and the radius squared plus the height times 2 pie radius.