In general, pink flowers tend to be an example of incomplete dominance of the gene for red flowers. Therefore, the phenotypic ratio of a cross between two pink flowers would be the same as the genotypic ratio of 1:2:1. In other words, 1 red to 2 pink to 1 white.
50% red and 50% pink in the F1 generation. Why?
(Let's use 'R' for the red allele and 'r' for the white)
Pink flowers are heterozygous: Rr
Red-flowered plants are homozygous red: RR
Therefore:
P: RR x Rr
RR can only produce one type of gamete with the R (red) allele
Rr produces 2 types of gametes, R (red) and r (white) in equal ratios.
If R meets R the offspring is red; if R meets r the offspring is pink.
So again, F1 is 50 RR (red), and 50% Rr (pink).
Sorry, I tried to do the Punnett-square here, but the spacing got warped and it all came out gibberish in the end.
There would be three purple plants and one with the recessive gene. Of the three expressing the gene, one would be homozygous dominant and two would be heterozygous dominant. So it would be three dominate gene plants to one recessive or two heterozygous to two homozygous.
Pink flowered plants will be produced if the two pink flowered plants are crossed.
50% Red:50% Pink
100% dominance, or 100% RR
1000
More true breeding white flowered plants. If the gene combination for white is WW and is dominant a cross of WW x WW would result in 100% WW (white flowered plants)
Beetroot plants do bear flowers. The flowers are produced in a dense spike-like inflorescence. The flowers are small and are borne in one to three-flowered glomerules with bracts on the lower half of the inflorescence and without bracts in the upper half of the inflorescence.
The offsprings of F1 plants are known as F2. The letter F denotes the filial generation and the number denotes subsiquest generations of crossing among themselves.
When offsprings in a plant are produced by vegetative propagation, these are like their parents only because recombination of genetic material is avoided due to absence of meiosis.
Ture
They are fine; expected ratios might not be seen simply due to chance.
The alleles that determine flower color in four o'clock plants show incomplete dominance. The florist should use pollen from white-flowered four o'clock plants to pollinate red-flowered four o'clock plants, or vice versa. She should then collect seeds from the plants after they are produced. All of these hybrid seeds will produce only pink-flowered four o'clock plants.
224
PP X ww or Pw X ww Because all Purple flower plants are dominant and express the color purple. This can be seen in a homozygous cross, or a heterozygous cross, ( shown above ) White plants, to breed true, must be in homozygous condition.
no
they are fine ; expected ratios might not be seen simply due to chance
they are fine; expected ratios might not been seen simply due to chance
All the offspring were purple because Mendel was dealing with simple genetic dominance. The purple true breeding parent was homozygous dominant and the true breeding white parent was homozygous recessive. When those two are crossed they create only heterozygous offspring (look up a punnett) and since this is simple dominance those heterozygous will show the phenotype of the dominant allele which is purple.
1000
1000
yes they have the phenotybe pp and pp so the only result is pp the recessive kind