1 out of every 4 the percent will be 25%
A test cross between a homozygous recessive and a heterozygous individual will yield 50% of offspring as homozygous recessive. This is because all the offspring will inherit one recessive allele from the homozygous recessive parent.
The probability that an individual heterozygous for a cleft chin and an individual homozygous for a chin without a cleft will produce offspring that are homozygous recessive for a chin without a cleft is fifty percent. You can calculate this by making a Punnet square.
A. Offspring with heterozygous genotype 100 percent B. Offspring with homozygous dominant genotype 0 percent C. Offspring with at least one copy of recessive gene 50 percent
All the offspring will be heterozygous with a phenotype showing the dominant trait. Let the alleles be H (dominant) and h (recessive). All the gametes from the first individual will be H, and from the other, h. Thus all the offspring must be Hh.
If 50% of the offspring show the dominant phenotype and 50% show the recessive phenotype, it is likely that one parent is heterozygous (Aa) for the trait and the other parent is homozygous recessive (aa). This would result in a 1:1 ratio of offspring showing each phenotype.
A test cross between a homozygous recessive and a heterozygous individual will yield 50% of offspring as homozygous recessive. This is because all the offspring will inherit one recessive allele from the homozygous recessive parent.
100% of the offspring will display the dominant trait because the homozygous dominant parent can only pass on the dominant allele. The offspring will inherit one dominant allele from the dominant parent and one recessive allele from the recessive parent, resulting in a heterozygous genotype expressing the dominant trait.
100 percent.
The probability that an individual heterozygous for a cleft chin and an individual homozygous for a chin without a cleft will produce offspring that are homozygous recessive for a chin without a cleft is fifty percent. You can calculate this by making a Punnet square.
A. Offspring with heterozygous genotype 100 percent B. Offspring with homozygous dominant genotype 0 percent C. Offspring with at least one copy of recessive gene 50 percent
The phenotype will show the dominant trait. All dominant traits mask recessive ones; If the genotype is heterozygous (One dominant and one recessive) the organism's phenotype will be dominant.
All the offspring will be heterozygous with a phenotype showing the dominant trait. Let the alleles be H (dominant) and h (recessive). All the gametes from the first individual will be H, and from the other, h. Thus all the offspring must be Hh.
If 50% of the offspring show the dominant phenotype and 50% show the recessive phenotype, it is likely that one parent is heterozygous (Aa) for the trait and the other parent is homozygous recessive (aa). This would result in a 1:1 ratio of offspring showing each phenotype.
There is a 25% chance (1 in 4) that the offspring will be homozygous for the trait. This is because when both parents are heterozygous (Aa), they can pass on either the dominant allele (A) or the recessive allele (a) to their offspring, resulting in a 1 in 4 chance of the offspring receiving the recessive allele from both parents and becoming homozygous (aa) for that trait.
A cross between two homozygous parents will form a 100 percent chance of a heterozygous offspring. One homozygous parent must have the dominant allele, and the other must have the recessive allele. So, if the circumstances are correct, these characteristics will make for a 100 percent chance of a heterozygous offspring.
0 percent.
Here's an example: two chickens have the phenotype of white feathers and brown feathers. What percentage of the chicks will have the recessive color? First, you have to see the parents' phenotypes. To get the answer, a good trick is to use the box. Draw a box and cut it into 4 pieces. Put one of the parent's phenotypes (w and B) on the top, and the other parent's (w and B) on the right side going down. Whichever trait is dominant (brown) MUST be capitalized. Then, cross the two parents. first box on the top left would read 'ww.' The one below it is 'Bw' (put the dominant first). The right top is 'Bw' and the one below it is 'BB'. So if there were 4 offspring, these would be their genotypes: 'ww', 'Bw', 'Bw', and 'BB'. The only offspring that would have the recessive trait is the 'ww' child, because dominant overpowers recessive. So 25% would have the recessive trait and 75% would have the dominant trait! Good luck, and the box may be confusing now, but it does work!!!