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4.0 g of lactose substrate

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What is the saturation point in an enzymatic reaction called?

The saturation point in an enzymatic reaction is called Vmax, which represents the maximum rate of reaction when all enzyme active sites are bound to substrate molecules. At Vmax, the enzyme is saturated with substrate and the rate of the reaction cannot increase further with an increase in substrate concentration.


Is Vmax a threshold of substrate concentration for initiation of an enzymatic reaction?

Oddly phased question in my opinion. Vmax is only effected by the amount of enzyme present in the reaction. Substrate concentration has zero effect on Vmax. There for I believe the answer in no. {Enzyme concentration is responsible for this}


When substrate concentration is equal to km what will be the initial velocity?

When the substrate concentration is equal to the Michaelis constant (Km), the initial velocity of the enzyme-catalyzed reaction will be half of the maximum velocity (Vmax) of the reaction. At Km, half of the enzyme active sites are filled with substrate, leading to half of maximum velocity being reached.


Describe the relationship between substrate concentration and the initial reaction rate of an enzyme-catalyzed reaction Is this a linear relationship What happens to the initial reaction rate as sub?

As the substrate concentration increases so does the reaction rate because there is more substrate for the enzyme react with.


The initial rate of an enzyme catalysed reaction depend on?

Based on Michaelis-Menten enzyme kinetics, the initial rate of reaction, vi, is dependent on maximum rate Vmax, substrate concentration [S], and the enzyme's Michaelis constant Km, which represents the the tendency of the substrate/enzyme complex to dissociate. The dependence on enzyme concentration is factored into the maximum rate. The equation to describe this is: vi = Vmax([S]/(Km+[S])) Follow the link below for details.

Related Questions

How can you determine the maximum velocity of a reaction by calculating Vmax?

To determine the maximum velocity of a reaction, you can calculate Vmax by plotting a graph of reaction rate against substrate concentration and finding the point where the reaction rate levels off. This point represents the maximum velocity that the reaction can achieve under the given conditions.


What happens to the rate of enzyme concentration when you increase substrate concentration?

The rate of enzyme reaction is increased when the substrate concentration is also increased. However, when it reaches the maximum velocity of reaction, the reaction rate remains constant.


How does the presence of competitive inhibitors impact the maximum reaction rate (Vmax) of an enzyme?

Competitive inhibitors decrease the maximum reaction rate (Vmax) of an enzyme by competing with the substrate for the enzyme's active site, which reduces the efficiency of the enzyme-substrate complex formation and slows down the rate of the reaction.


Why was there no increase in the reaction rate with 8.0 g. of substrate as compared to 4.0 g. of substrate What would you need to add to see an increase in the reaction rate with 8.0 g. of substrate?

because the amount of the other variables are the same, no change. once 4.0 g of lactose substrate or whatever it is is at it's maximum reaction rate, it can do no one reaction therefore there was no reaction in the 8.0 g of substrate. Because the reaction volume was also doubled; so there was no change in concentration of substrate.


What is the saturation point in an enzymatic reaction called?

The saturation point in an enzymatic reaction is called Vmax, which represents the maximum rate of reaction when all enzyme active sites are bound to substrate molecules. At Vmax, the enzyme is saturated with substrate and the rate of the reaction cannot increase further with an increase in substrate concentration.


Is Vmax a threshold of substrate concentration for initiation of an enzymatic reaction?

Oddly phased question in my opinion. Vmax is only effected by the amount of enzyme present in the reaction. Substrate concentration has zero effect on Vmax. There for I believe the answer in no. {Enzyme concentration is responsible for this}


What is the relationship between substrate concentration and enzyme activity?

At low substrate concentrations, the rate of enzyme activity is proportional to substrate concentration. The rate eventually reaches a maximum at high substrate concentrations as the active sites become saturated.


When substrate concentration is equal to km what will be the initial velocity?

When the substrate concentration is equal to the Michaelis constant (Km), the initial velocity of the enzyme-catalyzed reaction will be half of the maximum velocity (Vmax) of the reaction. At Km, half of the enzyme active sites are filled with substrate, leading to half of maximum velocity being reached.


Describe the relationship between substrate concentration and the initial reaction rate of an enzyme-catalyzed reaction Is this a linear relationship What happens to the initial reaction rate as sub?

As the substrate concentration increases so does the reaction rate because there is more substrate for the enzyme react with.


What does your data indicate about the optimum substrate concentration for this lactase catalyzed reaction?

The data indicates that the optimum substrate concentration for the lactase-catalyzed reaction is typically at a concentration where the enzyme active sites are mostly saturated with substrate molecules, leading to maximum reaction rate. Beyond this point, increasing substrate concentration may not significantly increase the reaction rate due to enzyme saturation. This optimum concentration ensures efficient enzyme-substrate binding and catalytic activity.


How do you calculate Michaelis Menten constant?

The Michaelis-Menten constant (Km) is calculated by determining the substrate concentration at half of the maximum reaction rate (Vmax). This value can be obtained by plotting reaction rates against substrate concentrations and identifying the point where the reaction rate is half of Vmax. Km represents the affinity of the enzyme for its substrate.


What should be done in order to keep the rate constant over the entire time course?

add more substrate. The rate of the reaction drops when the enzyme no longer has a maximum number of substrate molecules to interact with. Above the maximum substrate concentration, the rate will not be increased by adding more substrate; the enzyme is already working as fast as it can. An enzyme can catalyze a certain number of reactions per second, and if there is not sufficient substrate present for it to work at its maximum velocity, the rate will decrease. Therefore, to keep the enzyme working at its maximum, you must add more substrate.