Making babies
The man's genotype is CcFf. The woman's genotype is CcFf. These genotypes only apply if curly hair is dominant to straight hair. Freckles is dominant to no freckles. Also if a man who is heterozygous for both curly hair and freckles who then marries a woman with the same genotype.
The genotype of the man is A negative/O negative inheriting the A neg from his mother and O negative from his father. [Father's genotype is B positive/O negative. Mother's genotype is B positive/A negative.]
The albino woman has to be AA. So the man has to be either AA or Aa in order to be normal. So if they have a baby and its albino it has to contain the AA gene. a a A Aa | Aa ---------------- A Aa | Aa doesn't work.. All outcomes are normal. a a A Aa | Aa ----------------- a AA | AA these combination outcomes 50% chance of an albino baby. This means the man is Aa Heterozygous dominant.. the mother is AA homozygous recessive.. and the baby is the same as the mother. AA...
Yes if both the male and female parteners are normal in their phenotypes as said above- CC and AS.Their all generations are normal without any problems. But if one partner is normal for one phenotype(CC) and abnormal for other phenotype(ss) and marriage is done with other partner who is normal for one phenotype(AS) and abnormal for other phenotype(cc) the generations obtained are varied- i.e. females are mostly carriers in these cases and males are more susceptible to attain the abnormality in more percentage. If female is CC & ss married with male cc & AS then female progeny are carriers for both phenotypes and males attain abnormality of 'cc' as he has only one X chromosome. This marriage exhibits criss cross inheritance in their families.
It depends on the genotype of the parents: If they are AO and BO the child could be all of the 4 ABO-Bloodtypes: AO (= bloodtype A) BO (= bloodtype B) AB (= bloodtype AB) OO (= bloodtype O) If they are AA and BB the child could only be bloodtype AB If they are AO and BB the Child could be AB, or B (BO) If they are AA and BO the child could be AB or A (AO) In short, when the genotype is not given, the child can have any of the ABO-Bloodtypes
Yes.
A woman with type A blood may have genotype AO or AA. The heterozygous type is AO.
I would call her a common-looking woman. Average
She is a carrier of hemophilia but does not have the condition
If an AC genotype man and an AS genotype woman marry, each of their children has a 25% chance of being born with a sickle cell disease (SS genotype), a 50% chance of being a carrier like their parents (AS genotype), and a 25% chance of having a normal genotype (AA).
The woman would have blood type A. A genotype of IA indicates the presence of the A antigen on red blood cells.
The woman would have genotype AO (IAIA) for blood type A, the man would have genotype BO (IBIB) for blood type B, and their child with blood type O would have genotype OO (ii). The child inherited one O allele from each parent.
no they can only have children with as as as as
The man's genotype is CcFf. The woman's genotype is CcFf. These genotypes only apply if curly hair is dominant to straight hair. Freckles is dominant to no freckles. Also if a man who is heterozygous for both curly hair and freckles who then marries a woman with the same genotype.
The mother's genotype is rr. The daughter would inherit one recessive allele from her mother because her mother has only recessive alleles. Because the daughter is green eyed, she would inherit a dominant allele from her father. The brown-eyed daughter's genotype would be Rr.
50% of the cross would be brown eyes and 50% would be blue eyes
The genotype of the man is A negative/O negative inheriting the A neg from his mother and O negative from his father. [Father's genotype is B positive/O negative. Mother's genotype is B positive/A negative.]