Black is B and white b in this example so parents are Bb and bb. Genotypic ratio is 1 Bb:1 bb. Phenotypic ratio is 1 black:1 white.
Dominant: The trait observes when at least one dominant allele for a characteristic is inheritedRecessive: A trait that is apparent only when two recessive alleles for the same characteristic are inheritedHomozygous: Two of the same alleles for the same alleles (RR or rr)Heterozygous: Genotypes made of two different alleles (Rr)Pure breed: same definition as homozygousHybrid: same definition as Heterozygous
If the allele is dominant, you only need one copy for it to be expressed in the phenotype (you have TWO alleles for each trait) If the allele is dominant, you only need one copy for it to be expressed in the phenotype (you have TWO alleles for each trait)
The F1 (first filial) generation is always 100% heterozygous.This is because the F1 generation is defined as the offspring of pure-breeding (homozygous) parents carrying different alleles from each other, e.g. AA x aa. All the offspring must be Aa, in other words heterozygous.
The parents of an albino plant are likely to be heterozygous for the gene controlling albinism. This means they carry one normal allele and one albino allele. When these two alleles combine in the offspring, it results in the expression of the albino trait.
One way to determine the male's genotype would be to breed him to females with a known genotype of Black-Black. If any resultant calves were born with a white coat, you would then know that the male were Black-White. If calves were consistently black coated, you could be fairly certain he was also of the Black-Black genotype.
To determine the genotype of a white ram, breed him with black females. Black females are homozygous recesive for the black trait, a. If the ram is homozygous dominant, all offspring will be white (and heterozygous). If the ram is heterozygous, approximately half of it's offspring will be white and half will be black.
True for the most part, if you breed two homozygous animals then it's a 50/50 chance of the offspring breeding true to one parent. If you breed a Homozygous animal and a heterozygous animal then the homozygous animal will breed true at least 90% of the time.
It depends on the horse's genetics. Chestnut is recessive to black, therefore a chestnut horse always carries two chestnut genes but a black horse could be carrying two black genes OR a black and a chestnut, but the black is dominant therefore the horse has a black coat. Think of it as the black coat always sits 'on top' of the chestnut coat so if a horse has a black gene it will always show up but chestnut will only show up if there are no black genes at all. If you breed a homozygous dominant (two black genes) black horse to a chestnut, the foal will always be heterozygous dominant black. (One black gene and one chestnut gene) If you breed a heterozygous dominant (one black one chestnut) black horse to a chestnut, the foal has a 50% chance of being heterozygous dominant black and a 50% chance of being homozygous recessive chestnut. (two red genes) If you have no idea what your black horse's color genes are, think of it as having a 75% chance of a black foal, 25% chance of a chestnut foal.
Dominant: The trait observes when at least one dominant allele for a characteristic is inheritedRecessive: A trait that is apparent only when two recessive alleles for the same characteristic are inheritedHomozygous: Two of the same alleles for the same alleles (RR or rr)Heterozygous: Genotypes made of two different alleles (Rr)Pure breed: same definition as homozygousHybrid: same definition as Heterozygous
To determine if a black guinea pig is homozygous or heterozygous for black fur, you would need to cross it with a white guinea pig. If the offspring are all black, then the black guinea pig is homozygous. If any white offspring are produced, then the black guinea pig is heterozygous.
here is my answer found using a Punnett Square: for one trait (lets use hair color) both guinea pigs are hazel. But, because they are heterozygous they also have the resessive gene for white. So, you cross Hh with Hh. You then have this genotypic ratio: 1 HH:2 Hh:1 hh This can be translated into a phenotypic ratio: 3 hazel: 1 white The final answer: You will have 25% homozygous dominant, 50% heterozygous (showing the dominant), and 25% homozygous recessive.
yes because if it is heterozygous dog that means that it has a dominant gene ( big ) and a recessive gene ( small ) and that means the dog is Tt capital t is dominant and if they breed with another homozygous recessive dog that means that out of every 4 puppies 2 will be big and 2 will be small ( p.s homozygous means that you have all dominant or recessive genes )
Heteroygous means hybrid. So if both parents are heterozygous, they're both hybrids. Homozygous means that they are purebred. The chance is 50%. 25% chance of it being reccesive and 25% chance of being dominant. Thank you I'm only 11 and am in a advanced science class.
homozygous first filial organism,which can undergo mutation or which may be cross-linked or made to breed with other.
It is called CODOMINANCE if the alleles each express when the phenotype is heterozygous. Let's look at the following situation. There are snapdragon flowers that are homozygous (having 2 of the same allele) for red. Let's call them R. There are also snapdragon flowers that are homozygous for white. Let's call them r. If you take one of the RR flowers and breed it with a rr flower, you will get Rr. If one of the alleles is dominant, then the flower will be the color of the dominant allele. If R (red) is the dominant allele, then all of the offspring will be red; if r (white) is the dominant allele, then they will be white. However, if they are codominant, then if the genotype is heterozygous (Rr), then the alleles will both express- in this case, the offspring would be pink. Hope I helped!
Heterozygous - White gene carrier Homozygous - No white gene White tigers are not albinos and do not constitute a separate subspecies of their own and can breed with orange ones, although all of the resulting offspring will be heterozygous for the recessive white gene, and their fur will be orange. The only exception would be if the orange parent was itself already a heterozygous tiger, which would give each cub a 50% chance of being either double-recessive white or heterozygous orange. If two heterozygous tigers, or heterozygotes, breed on average 25% of their offspring will be white, 50% will be heterozygous orange (white gene carriers) and 25% will be homozygous orange, with no white genes. In the 1970s a pair of heterozygous orange tigers named Sashi and Ravi produced 13 cubs in Alipore Zoo, of which 3 were white. If two white tigers breed, 100% of their cubs will be homozygous white tigers. A tiger which is homozygous for the white gene may also be heterozygous or homozygous for many different genes. The question of whether a tiger is heterozygous (a heterozygote) or homozygous (a homozygote) depends on the context of which gene is being discussed. Inbreeding promotes homozygosity and has been used as a strategy to produce white tigers. (From Wikipedia)
Buckskin or Smoky Black