Yes. Two normal-visioned parents can produce a color blind child only if both the parents have are heterozygous. To determine the phenotypes of the parents, you will have to look at their parents.
Morgan could have crossed a white-eyed male fruit fly (homozygous for the white-eye allele) with a wild-type red-eyed female fruit fly (homozygous for the red-eye allele). This cross would result in the F1 generation being all red-eyed females (heterozygous for the white-eye allele) and red-eyed males (hemizygous for the red-eye allele). Then, he could mate the F1 red-eyed females with each other to produce the F2 generation, which would include white-eyed females if the F1 females were carriers of the white-eye allele.
The scientist could conclude that the females choose mates.
If glycolysis could not happen in a cell, the cell would not produce ATP molecules.
the human protein coded for by the human gene
The organism could produce 32 different gametes without crossing over. This is calculated as 2^n, where n is the number of chromosome pairs. In this case, 2^5 = 32.
No. They could have an A- child, but not A+.
Generally, all females can produce pups.
1.They could camaflage 2.The males get pregnate 3.Females produce the eggs
P1 stands for "parental generation." This refers to the parents (mom and dad) who start off the pedigree. The P1 generation can then produce offspring (called the F1, or "first filial generation"). The F1 generation could then produce the F2 generation (or "second filial generation").
Parental Consent.
In short, hemophilia has nothing to do with colorblindness, but YES, they could have a colorblind child if she is a carrier for the colorblindness gene. Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A woman will carry the colorblindness gene if: a. Her father is colorblind b. Any of her offpsring are colorblind She may carry the colorblindness gene if: a. Male family members (brothers, uncles, etc.) are colorblind A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy). So, If a woman has normal vision (assuming she does not have a family history of colorblindness), XX, and a man is colorblind, xY, they have several different chances for different offspring: Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) The short answer is that ALL CHILDREN WILL HAVE NORMAL VISION. However, all daughters will be CARRIERS, meaning they can pass colorblindness on to their children.
you should wait until your 16, but yes you could get it at 14 with parental consent.
Since males produces millions of sperm in each ejaculate and females produce about 300 million eggs in a life time, it would could be hundreds.
yes they could with a dildo
no. the males and females will alternate to collect food from the sea, but they will stay where the male or females could find them..
Any type of parental voids.
Young people could interact without parental supervision.