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What else can I help you with?
Which of the following circles have their centers on the y-axis (x-0)squared (y 5) squared74?
Yes, it does.
What is the length of the circles radius for the equation x2 plus y2121?
If you mean: x^2 + y^2 = 121 then the radius is the square root of 121 which is 11
What circles have their centers on the y-axis?
The circles that have their centers on the y-axis are those that have the equation x^2 + (y-k)^2 = r^2, where k is the y-coordinate of the center of the circle and r is the radius of the circle. In this case, the x-coordinate of the center is 0 since it lies on the y-axis.
Animal that starts with a y and z?
· Yellowhammer · Zone-tailed Hawk
What does hawk at a flea market mean?
"Hawk" in that context means "to sell" as in the more common phrase "hawk your wares"
Which of the following circles have their centers on the x-axis Check all that apply?
Do you mean the following? (x + 16)2 + (y + 3)2 = 17 (x + 3)2 + (y - 6)2 = 44 You can find the center of these circles by using the negatives of the numbers subtracted by the x and y variables. In this case, the circles are centered at the points (-16, -3) and (-3, 6). The one in which both the x and y co-ordinates are negative would be the one in the third quadrant. And try to phrase your questions better. That could just as easily be read as "ax + 162 + y + 32 = 17bx + 32 + y - 62 = 44", which makes no sense.
Kitty Hawk mean temp for June?
The mean tempurate for Kitty Hawk in June is about 75 degrees. Hope this helps!
What does taka mean in Japanese?
In Japanese, "taka" means Hawk, or Eagle.
What does hawk mean in Greek mythology?
Hawk means strong and brave in greek mythology
What does it mean to see a hawk after someone dies?
Nothing, except you saw a hawk, after a death.
What is the Differential equation of circles tangent to x-axis?
[1+(y')2]3 = [yy"+1+(y')2]2
What does it mean for Aboriginal Australians to have a brown hawk follow them?
i am not sure. it could mean that they had a well trained pet brown hawk that followed them everywhere???...
