of course it does water has a weight to it like anything else, the weight of the vehicle remains the same obviously but the water in it will add to the weight
Submerged unit weight refers to the weight of soil or material per unit volume when submerged in water, taking into account buoyancy effects. Submerged weight refers to the total weight of an object or material when it is submerged in a fluid, including both its actual weight and any buoyant force acting on it.
Submerged "out-of-water". That is not possible. It is either submerged or it is out of water. Even when an object is submerger or partically submerged it will not weigh less. The physical characteristics (weight) of the object cannot be changed. The object, when placed in water will displace a certain amount of water and the object will float if the weight of the displaced water is more that the weight of the object. The object will then sink if it weighted more that the weight of the water it displaces. That said, the actual weight of the object doesnt change but if a scale were attached to it while hanging in air, it would read greater that when the object is floating or submerged in water.
The Weight Change.
The submerged will float
The independent variable would be the weight of the vehicles being investigated. This is the variable that is intentionally changed or manipulated by the researcher in order to observe its effect on the speed of the vehicles, which would be the dependent variable.
No, it is equal in volume.
To calculate the depth a boat is submerged in water, you can use Archimedes' principle, which states that the buoyant force on an object is equal to the weight of the water displaced. By comparing the weight of the boat to the weight of the water displaced, you can determine the depth the boat is submerged. This can be calculated using the formula: Depth submerged = (Weight of the boat) / (Density of water * g), where g is the acceleration due to gravity.
The buoyant force on a submerged object depends on the volume of the object. It is equal to the weight of the fluid displaced by the object, which is determined by its volume. The weight of the object itself affects the net force experienced by the object when submerged.
The unit weight of submerged soil: Submerged Density (kN/m3) = Saturated Density - Water Density Water Density = 9.81 kN/m3
The buoyant force acting on a fully submerged object is equal in magnitude to the weight of the water displaced. This is known as Archimedes' principle, which states that the buoyant force is equal to the weight of the fluid displaced by the submerged object.
The buoyant force on any object in water is equal to the weight of the displaced water, regardless of how much of the object is submerged.
You will find that such an object will weigh its weight on land minus the weight of the water it displaceswhen submerged. It doesn't seem possible, but it is true. This kind of result is called 'counterintuitive'.