If it's the older 50s or 60s motor:
#1- remove shift rod coupler plate on side of intermediate housing w/2 screws, then see inside a coupler with 2 3/8" capscrews. Remove the bottom capscrew. this will allow you to separate the lower unit after you remove the 6 screws underneath the flange and the one long one with it's head up. Seven total.
#2- pull the lower unit down, the drive shaft and the lower part of the shiftrod will come out along with the lower unit. Water pump too. This is a good time to check the impeller. If it's old or partially messed up, buy a new one.
#3- Remove the 6 screws at the c/l of the prop shaft and the whole gear assembly will come apart.
Buy a Sealoc book and learn all about these motors and it will save a lot of grief/expense !!!
It is 1941 1942. I own the same motor
A Johnson outboard, model number CD-15, would be a 5.5 hp from 1958.
50:1
At the end of the rope stupid
It should be 50:1.
50 to one
debends on the block aluminum will be around 45-50lbs
between 90-120
The required spark plug air gap for the 83 model, 15 hp Johnson is .030 in.
remove right side under dash panel remove blower cover unplug motor remove motor and blower regulator swap regulator on to new motor note all u need is a philpps head and a 15 and 25 torques
The 15 hp Johnson will run well on a 50:1 ratio, roughly one pint 2 cycle oil, to six gallons of fuel.
Depending on the year model, a 15 hp Johnson outboard is listed as having a dry weight of 70 - 85 lbs.