To mix oil at a 50:1 ratio in a 20-liter tank, you need to determine the amount of oil required. For a 50:1 ratio, there is 1 part oil to 50 parts fuel, so you divide the total volume by 50. In this case, you would need 0.4 liters of oil (20 liters ÷ 50) to achieve the desired ratio.
To find the amount of oil needed for a 501 ratio in 5 liters of fuel, you divide the total volume by the ratio. In this case, 5 liters divided by 501 equals approximately 0.00998 liters of oil, which is about 10 milliliters. Thus, you would need roughly 10 milliliters of oil for 5 liters of fuel to achieve a 501 ratio.
12.8 u.s. ounces
It is 501/165. This can be simplified if you so wish.
501 is evenly divisible by 3, 167, 501 and 1. 501 / 3 = 167 501 / 167 = 3 501 / 501 = 1 501 / 1 = 501
They are -501 and +501
98% of 501= 98% * 501= 0.98 * 501= 490.98
60% of 501= 60% * 501= 0.6 * 501= 300.6
105% of 501= 105% * 501= 1.05 * 501= 526.05
The factors of 501 are: 1 3 167 501
501 is divisible by: 1, 3, 167, 501.
The positive integer factors of 501 are: 1, 3, 167, 501
1 x 501, 3 x 167 = 501