The fuel to oil ratio for a 1988 model, 8hp Johnson outboard, would be 50:1, six gallons of fuel, to one pint of two cycle oil.
The spark plugs on a 1988 model, 70hp Johnson outboard, should be gapped to .030in.
The 1988 model, 28hp Johnson outboard, requires a 50:1 fuel to oil ratio. This is roughly, one pint of 2 cycle oil, to six gallons of fuel. If you have the same motor I have which is a 1988 Johnson 28 hp 2 stroke then the mixture is 100:1. The answer provided above is wrong. This is 8 ounces of 2 stroke oil to 6 gallons of gas. I have had this motor since it was new and it still runs great today.
23 years old made in 1988
50:1
50:1 i have a 1988 johnson 88 spl thats what i run and it runs sweet
To determine the year of your Johnson 20hp outboard with model number FD-20C and serial number J2604167, you can refer to the Johnson outboard motor's serial number guide, which typically indicates that the first digit of the serial number represents the year of manufacture. In this case, "J" typically corresponds to 1988. Therefore, your outboard motor is likely from the year 1988.
Model number J20ELCCA is a 20 hp Johnson outboard, electric start, long shaft, 1988 model, outboard engine.
If this is not a VRO injected engine, mix one pint of 2 cycle oil to every six gallons of fuel, to obtain a 50:1 ratio.
0.035 is the gap size
1988
The fuel to oil ratio, for a 1988 model Suzuki outboard is 50:1, roughly 1 pint of 2 cycle oil, to six gallons of fuel.
1988