50;1
The gas to oil ratio is 50 to 1 50: 1 I have the same motor, good luck
The 1977 model, 20 hp Mercury outboard, requires a 50:1 fuel to oil ratio.
The 20 hp Mercury outboard requires a 50:1 ratio, roughly one pint of 2 cycle oil, to six gallons of fuel.
The ratio is 50 parts fuel to 1 part 2 cycle oil, or the standard 1 pint to 6 gallons mix.
The 20 hp Mercury outboard requires a 50:1 ratio, one pint of 2 cycle oil, to six gallons of fuel.
This is the ratio of gasoline to outboard motor oil. 50:1 is the most common mix ratio. This equates to just about 1/2 quart of outboard oil per 6 gallon tank of gas.
To calculate the amount of oil needed for a 50:1 ratio, you can divide the total volume of gas by 50. For 20 liters of gas, you would add 20 liters ÷ 50 = 0.4 liters of oil. Therefore, you should add 0.4 liters of oil to 20 liters of gas at a 50:1 ratio.
17.6 ounces of oil for 2.75 gallons of gas to get a 20:1 mix ratio
20:1
To achieve a 50:1 gas-to-oil ratio for 1 liter of gasoline, you would need 20 milliliters of oil. This is calculated by dividing 1,000 milliliters (1 liter) by 50, which equals 20 milliliters of oil. Therefore, mix 1 liter of gasoline with 20 milliliters of oil to obtain the correct ratio.
To determine how much oil to add to 20 gallons of gas at a 50:1 ratio, you would divide the number of gallons of gas by the ratio. For 20 gallons, you would calculate 20 gallons ÷ 50 = 0.4 gallons of oil. Since there are 128 ounces in a gallon, this is equivalent to 0.4 x 128 = 51.2 ounces of oil. Therefore, you should add approximately 51.2 ounces of oil to 20 gallons of gas.
20:1