The antilog?
a log is an exponent, so as an antilog just means you reapply that exponent to the correct base. Log implies base 10, so antilog means use that number as an exponent of 10.
If you are using log tables, first separate the whole number part and the decimal part of the log ( they are both negative) then add -1 to the whole number part and +1 to the decimal part. (one is called the characteristic and the other is called the mantissa, but I don't remember which is which now) This creates a positive decimal that you can look up in the log table. The negative integer part becomes an exponent of 10. Put them together and you get an answer in scientific notation.
Ex: find antilog of -3.5
(-3 -1) + (-.5 + 1) ==> (-4) + (+.5)
look up .5 in the log tables and you get 3.1623 and the -4 becomes 10-4
Put them together by multiplying (adding logs means multiplication of antilogs)
to get the final answer 3.1623 x 10-4
d/dx (e-x) = -e-x
d = 2(n = 265782341)
You cant find the area of the throat because the throat is 3-D and the area is only for 2-D measurements
9x2 - 12x + 4 = 0 is of the form ax2 + bx + c = 0 where the discriminant, D, can be found by D = b2 - 4ac First, you find the values of a, b and c: a = 9 b = -12 c = 4 Now you can find D: D = (-12)2 - (4)(9) = 144 - 36 = 108 D = 108
29
The answer depends on what information you have. If you know the first number, a, and the common difference d, (where d is negative), then the nth term is a + (n - 1)*d : exactly the same as in an increasing linear sequence. The only difference is that d is negative instead of positive.
Whether the sequence is increasing or decreasing makes no difference. The only difference is that the common difference d will be a negative number.
tn = a + (n - 1)d where a is the first term and d is the difference between each term.
The nth term is Un = a + (n-1)*d where a = U1 is the first term, and d is the common difference.
a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.
To find the first term of an arithmetic progression (AP), you need at least two pieces of information: the common difference and either the second term or the sum of the first few terms. The first term can be represented as ( a ), and the ( n )-th term can be expressed as ( a_n = a + (n-1)d ), where ( d ) is the common difference. If you know the second term, you can rearrange it to find ( a = a_2 - d ). Without specific values or additional context, the first term cannot be determined.
The formula used to find the 99th term in a sequence is a^n = a^1 + (n-1)d. a^1 is the first term, n is the term number we wish to find, and d is the common difference. In order to find d, the pattern in the sequence must be determined. If the sequence begins 1,4,7,10..., then d=3 because there is a difference of 3 between each number. d can be quite simple or more complicated as it can be a function or formula in of itself. However, in the example, a^1=1, n=99, and d=3. The formula then reads a^99 = 1 + (99-1)3. Therefore, a^99 = 295.
It is the equivalent to Rh negative blood. D is the antigen present on commonly termed Rh+ red cells, and the D antigen is missing on D-negative blood.
negative :D
The given sequence is an arithmetic sequence with a common difference of 4 between each term. To find the nth term of an arithmetic sequence, we use the formula: nth term = a + (n-1)d, where a is the first term, d is the common difference, and n is the term number. In this case, the first term (a) is -3, the common difference (d) is 4, and the term number (n) is the position in the sequence. So, the nth term of the given sequence is -3 + (n-1)4 = 4n - 7.
In an arithmetic series, the common difference ( d ) can be found by subtracting any term from the subsequent term. For example, if you have two consecutive terms ( a_n ) and ( a_{n+1} ), the common difference is calculated as ( d = a_{n+1} - a_n ). You can also determine ( d ) using the formula for the ( n )-th term, ( a_n = a_1 + (n-1)d ), if you know the first term ( a_1 ) and any other term.
This is an arithmetic sequence with the first term t1 = 1, and the common difference d = 6. So we can use the formula of finding the nth term of an arithmetic sequence, tn = t1 + (n - 1)d, to find the required 30th term. tn = t1 + (n - 1)d t30 = 1 + (30 - 1)6 = 175