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What else can I help you with?
What is heat loss formulae of water flow through PPR-C pipe line?
you have first to know the thermal conductivity of PPR that you are dealing with. normally, this is in range between 0.1 to 0.24 W/MK .then you apply this formula Q(IN WATTS) =Thermal Conductivity/MK)*A( surface area for the pipe M2 )temperature difference between fluid inside pipe and temprture of pipe surface K)/(thickness of the pipe M)
How do air conditioning calculate?
If you are looking for an easy method that is not based in scientific data try this: Heating requirement is the same as cooling. To calculate Btu needed to cool look at the furnace for input Btu then multipy that by effeciency of unit. Now think about the coldest day the furnace will provide okay heating such as 5 degrees outside and 68 degrees inside. Subtract those and you have 63 degrees. If you heating Btu was 80000 input and 80% efficient, you need 64000 btu to heat 63 degrees. Do similar math to hottest day and desired inside cool temperature. Maybe 103 degrees outside and 72 degrees inside. That is 31 degrees difference. Use heat math of 64000 Btu for 63 degree which is very roughly 1000 Btu per degree. Apply that to cooling and it's roughly 31000 Btu, or around 2-1/2 ton cooling. Please don't bark at me about the basic nature of my math-I thought I would explain this as a method to start or get an idea. There is a method that accounts for all factors but no way could I explain it. Also, if using electric heat your btu will be about 4.5 per watt and no efficiency applies. The watts can be found on the inside of the furnace above the blower.
How much power in watts is needed to cut a lawn in 50 minutes if the work involved is 100000 joules?
The power needed to cut a lawn in 50 minutes, given that the work done is 100,000 joules, can be calculated by dividing the work by the time. 100,000 joules of work in 50 minutes is equivalent to 33.33 watts of power.
How much power is needed for a 200 kg person to climb 40 m up in 40 seconds?
Power = 200*9.8*40/40 Watts = 1960 Watts.
The amount of power needed to do 10 joules of work in 1 second is?
10 joules per second = 10 watts
How much power is needed to do 1200 Joules of work in 90 seconds?
Power is measured in watts, or joules per second. So in 90 seconds, 1200 joules of work is equal to 1200/90 watts or 13.3 watts.
How many watts is 230v 1.30amps?
how many watts aew needed to power a 110 volt tv at 1.30 amp
When calculating power what 2 pieces of information are needed?
Work done (joules) and time taken (seconds) is the information needed to calculate power in watts (joules/second).
How much power is needed to perform 600 Joules of work in 120 seconds?
7.5 watts
5.0 amps watts?
To find the power in watts, multiply the current (5.0 amps) by the voltage (which is needed to provide the full power calculation). Without voltage information, we can't determine the power in watts solely from current (amps).
How many watts do 1 hertz have?
Hertz (Hz) is a unit of frequency, not power, so it doesn't have watts. Watts are a unit of power, measuring the rate of energy transfer or consumption per second. The relationship between watts and hertz would depend on the specific application or device involved.
How much heat is in 1000 watts?
1000 watts is a measure of power, not heat. Power is the rate at which energy is used or transferred. To determine the amount of heat generated by 1000 watts, additional information about the time over which the power is used or the efficiency of the system is needed.
How much power is needed to do 648 joules of work in 100seconds?
Power is calculated using the formula P = W / t, where P is power, W is work done, and t is time taken. In this case, you would calculate power as 648 / 100 = 6.48 watts. Therefore, 6.48 watts of power is needed to do 648 joules of work in 100 seconds.
How many watts of power needed to light marina bay race circuit?
The power needed to light the Marina Bay Race Circuit for the Singapore Grand Prix is approximately 3,180,000 watts. This is achieved through a combination of floodlights and lighting systems strategically placed around the circuit.
