A line tangent to a curve, at a point, is the closest linear approximation to how the curve is "behaving" near that point. The tangent line is used to estimate values of the curve, near that point.
Get in function form. - 3X - Y = 4 - 1(- Y = 3X + 4) Y = - 3X - 4 ----------------------------solve for X and Y by the 0 out method - 3X - 4 = 0 - 3X = 4 X = - 4/3 --------------- Y = - 3(0) - 4 Y = - 4 -------------- Draw a line linking those points.
The length of an arc equals he angle (in radians) times the radius. Divide the length by the radius, and that gives you the ange. Measure out the angle on a protractor and draw the length of the radius at the begining and end of the angle. Then draw theportion of the circle with its center at the location ofthe angle and extending out to the radius.
go to google and type the cay ....... DUMB BUTTS
Draw a circle with its center at the origin and a radius of 3.
because you have to show your work and make shore its right
Draw a line from the center of the circle to the edge. Where this line intersects the edge draw a line 90 degrees to it. This line is the tangent at the point of intersection.
no. you have to draw it such that it doesn't.
No. A tangent is a ratio without units. A line of 5 metres has a measurement unit: metres.
A straight line that touches its outside corner
A tangent to a circle is a line which touches the circle once. That is, it does not pass through the circle, which would mean intersecting it twice. A way to form a tangent is draw any line from the centre point of a circle to its edge. A line on the edge perpendicular (at 90 degrees to) this line will be a tangent.
The default method for drawing a circle is to specify a center point and radius.You can draw circles using any of the following methods:Center-RadiusCenter-DiameterTwo pointsThree pointsRadius-Tangent-TangentConvert Arc to CircleTo draw a circle by specifying its center and radiusDo one of the following:Choose Draw> Circle>center, radiusOn the Draw 2D toolbar, click the Circle Center-Radius tool.Type circle and then press Enter.Specify the center point.Specify the radius of the circle.
BY DISCOVERING THE FORCE OF GRAVITY AND ALSO MADE THE THREE LAWS OF MOTION
You join the centres of the two circles. Divide this line in the ratio of the two radii. Draw the tangent from this point to either circle and extend it to touch the other circle.
you draw a triangle formed by the centers of the two circles and use pythagoean theorem
Draw a circle with centre O. draw a tangent PR touching circle at P. Draw QP perpendicular to RP at point P, Qp lies in the circle. Now, angle OPR = 90 degree (radius perpendicular to tangent) also angle QPR = 90 degree (given) Therefore angle OPR = angle QPR. This is possible only when O lies on QP. Hence, it is prooved that the perpendicular at the point of contact to the tangent to a circle passes through the centre. Answer By- Rajendra Meena, Jaipur, India. email: rajendra.meena21@gmail.com
First you draw a tringsl
A circle's tangent is exactly the same as a triangle's tangent. If you look at a circle, you can make the radius the hypotenuse. Then make a vertical line from the point, and a horizontal line from the center. If you look, you have a triangle made inside the circle. This is why angles can be measured in radians, a unit that is derived from the circumference of a circle.-------------------------------------------------------------------------------------------By doing a little calculus, we find that the slope of the equation of a circle-the slope of the tangent line-is given by the tangent of an angle.AnswerEverything written above is correct, but doesn't have anything to do with tangents (in the circle sense of the word). Suppose you're given an angle theta. Draw a circle together with two radii, one horizontal and the other at an angle theta from the first one. (So far, this is the same as above.) Now draw the tangent to the circle at X, the point where the non-horizontal radius meets the circumference. Let Y be the point where this tangent meets the horizontal line through the centre. Then, assuming the radius is 1, tan(theta) is the distance XY, which is the length of part of the tangent.