175g of water was heated from 15 to 88 C How many kilocalories were absorbed by the water?

Answer 1

First we take 88 degrees and we subtract 15 degrees. We get 73 degrees difference. Then we multiply our 175 g of water by the temperature increase of 73 degrees. We get 12,775 calories. To get Kilocalories we must divide our calories by 1000. Why don't you do that?

Answer 2

The specific heat for water is 4.184 J/g/deg. The equation to use is q = mC∆T where q is heat; m is mass of water; C is specific heat; and ∆T is the change in temperature. Thus..
q = (1000g)(4.184 J/g/deg)(85-15) = 2,050,160 J = 2050 kJ (assumes 1L H2O has mass of 1000g)

Answer 3

To calculate the energy absorbed by the water, use the formula: Q = mcΔT, where Q is the energy absorbed, m is the mass of water (175g), c is the specific heat capacity of water (1 cal/g°C), and ΔT is the change in temperature (88°C - 15°C). Plug these values into the formula to find the energy absorbed in calories, and then convert it to kilocalories by dividing by 1000.

Answer 4

13125 kcal

Answer 5

12.775

Answer 6

73

Answer 7

12.8 Kc

Answer 8

12.775