rams of X2O3 gas makes 2 atm pressure at 273 C in a 8.96 liter container. So, howmany g.mol is the molar mass of the X atom of the X atom (O:16)?
0.5atm
It would contain about that much gas. As much as u put into it.
It depends on the type of gasoline, and other factors such as temperature and pressure, but gasoline has an approximate density of 737.22 kilogram/cubic meter. 737.22 kilogram/cubic meter = 0.73722 kilogram/liter = 737.22 gram/liter 42.4 liters * 0.73722 kilograms/liter = 31.258 kilograms or since you wanted grams, not kilograms... 42.4 liters * 737.22 gram/liter = 31258 grams(http://forum.onlineconversion.com/showthread.php?t=1114)
This problem can be solved with the ideal gas law. The original pressure and volume of the container are proportional the final pressure and volume of the container. The original pressure was 1 atmosphere and the original volume was 1 liter. If the final volume is 1.8 liters, then the final pressure is 0.55 atmospheres.
he much does a liter of rice weigh in grams
0
0.5atm
It would contain about that much gas. As much as u put into it.
6.34 cups 1 liter = 4.22 cups 1 cup = 0.23 liter
There is most likely a more efficient way to do this, but this is the best I can do for now.Notation: ( x , y ) where x is the amount of water in the 5-liter container and y is the amount of water in the 7-liter container1. Fill the five-liter container ( 5 , 0 )2. Pour the five-liter container into the seven-liter container ( 0 , 5 )3. Fill the five-liter container ( 5 , 5 )4. Fill the seven-liter container with the five-liter container, leaving 3 liters in the five-liter container ( 3 , 7 )5. Pour out the seven-liter container ( 3 , 0 )6. Pour the five-liter container into the seven-liter container ( 0 , 3 )7. Fill the five-liter container ( 5 , 3 )8. Fill the seven-liter container with the five-liter container, leaving 1 liter in the five-liter container ( 1 , 7 )9. Pour out the seven-liter container ( 1 , 0 )10. Pour the five-liter container into the seven-liter container ( 0 , 1 )11. Fill the five-liter container ( 5 , 1 )12. Pour the five-liter container into the seven-liter container ( 0 , 6 )
Around 0.12 percent, it differs in different countries depending on the environment and altitude.
It depends on the type of gasoline, and other factors such as temperature and pressure, but gasoline has an approximate density of 737.22 kilogram/cubic meter. 737.22 kilogram/cubic meter = 0.73722 kilogram/liter = 737.22 gram/liter 42.4 liters * 0.73722 kilograms/liter = 31.258 kilograms or since you wanted grams, not kilograms... 42.4 liters * 737.22 gram/liter = 31258 grams(http://forum.onlineconversion.com/showthread.php?t=1114)
You need to know the volume of liquid that contains the solid to answer this question. If you have one liter of a solution that contains 0.1 grams per milliliter, you can find the number of grams in the container through this calculation: 1 liter X 1000 ml/liter X 0.1 grams/ml = 100 grams of solid in the one liter of solution (the units for liters cancel out)
all of it - the air would expand to fit the entire container.
129 (grams per liter) = 129,000,000 micrograms per liter.
This problem can be solved with the ideal gas law. The original pressure and volume of the container are proportional the final pressure and volume of the container. The original pressure was 1 atmosphere and the original volume was 1 liter. If the final volume is 1.8 liters, then the final pressure is 0.55 atmospheres.
Multiply grams per liter by 0.001 to get grams per milliliter.