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The CO ligand can easily back-bond, accepting electron density from the metal centre through pi bonds.

This is because of the empty anti-bonding orbitals.

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How many electrons does the complex have using 18 electron rule Cr(n5-C5H5)(CO)2(PPh3)?

To determine the number of electrons in the complex Cr(n5-C5H5)(CO)2(PPh3), we can apply the 18-electron rule. Chromium (Cr) in the zero oxidation state contributes 6 electrons. Each CO ligand donates 2 electrons (total of 4 from 2 CO), and the PPh3 ligand contributes 2 electrons. The n5-C5H5 (cyclopentadienyl) ligand donates 5 electrons. Thus, the total electron count is 6 (Cr) + 4 (from CO) + 2 (from PPh3) + 5 (from n5-C5H5) = 17 electrons.


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