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5ca v2o5 5 cao 2 v in one process 2 5 1.54103 g of v o react with1.96103 g of ca a calculate the theoretical yield of v b calculate the percent yield if 803 g of v are obtained?
Wiki User
∙ 14y ago
Theoretical Yield
Calculate the theoretical yield when 1.54 × 103 g of V2O5 react with 1.96 × 103 g of Ca.
First, we find the limiting reactant:
1.54 × 103 g · 1 mol/181.881 g = 8.47 mol V2O5
1.96 × 103 g · 1 mol/40.078 g = 48.9 mol
The number of moles of Ca to react completely with 8.47 mol V2O5 is 8.47 mol V2O5 · 5 mol Ca/1 mol V2O5 = 42.4 mol
So Ca is in excess and we should use the molar amount of V2O5 to determine the theoretical yield of V.
8.47 mol V2O5 · 2 mol V/1 mol V2O5 = 16.9 mol V
Percent Yield What is the percent yield if 803 g of V are obtained?
First, find out how many grams the theoretical yield of V represents: 16.9 mol · 50.941 g/mol = 863 g
Then just divide the actual yield (given) by the theoretical yield: 803g/863g = 0.930 × 100% = 93.0%
(notice how the units cancel out completely to give a unit-free ratio)
Found this off a site.
It does not use your numbers but if you're good, you can try to compare and contrast to find your answer.
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∙ 14y ago
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Can you define percent yield in general terms?
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