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To answer this question, let's think about the excitation and relaxation processes involved. In the excitation process inside a deuterium lamp, an electrical arc between an oxide coated filament and an electrode excites D2 to D2*. Next, the D2* dissociates into individual D atoms. Let's call these D' and D''. Also, a photon of light is released. For an individual event, the total energy posssessed by D2* is apportioned between the kinetic energies of D', D'', and the photon. The sum of the kinetic energies of D' and D'' can vary from almost zero to the original energy of D2*. If the kinetic energies of D' and D'' are relatively small, the energy of the photon is large, and a shorter wavelength of light is emitted. If the kinetic energies of D' and D'' are relatively large, the energy of the photon is small, and a longer wavelenght of light is emitted. In a population of D2*, a distribution of kinetic energies of D' and D'' will result, allowing for a continuum spectrum to be emitted from the lamp.

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Q: 7 Why does a deuterium lamp produce a continuous rather than a line spectrum in the UV?
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Is D2SO4 concentrated sulfuric acid?

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How do you test metal?

You can heat it, put it in acids and bases, try to combine it with other metals, and measure physical properties like density, specific heat capacities (which can be considered thermal rather than physical), ductility (whether it deforms), and cleavage (how it breaks). You can also try to burn it or heat it and view its light spectrum (spectrophotometry).

Related questions

Why is the emission spectrum of hydrogen a line spectrum and not a continuous spectrum?

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Can you give a sentence with the word spectrum?

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What is the difference between a continuous spectrum an a line spectrum?

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