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PV=nRT (.855 atm)(.490L)=n(.0821)(306ºKel) .419=25.1n n=.0167 moles O2 .5344g O2 old answer by some slob: what the HELL. that makes no sence. well to an 11 year old. almost 12. =]

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15y ago
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15y ago

p=21+751=772 Torr pv=nRT (772\760)5=n.0.082(23+273) 5.079=24.272n n=.209 mole

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13y ago

9.76x10-3 both are the same

(0.00976)

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13y ago

0.00976 (apex)

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14y ago

0.00976

Things would happen

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0.0135

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0.0135

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0.0113

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Q: A 250.0mL sample of oxygen gas was collected over water at a temperature of 25C and 750.0 nm Hg How many moles of oxygen gas were there in this sample if the vapor pressure of water at 25C is 23.8 mm?
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