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What is the volume percent concentration of hexane in a solution made by mixing 50.0 mL of hexane with 1.0 L of pentane?
To calculate the volume percent concentration of hexane in the solution, you need to determine the total volume of the solution first. Mixing 50.0 mL of hexane with 1.0 L of pentane gives a total volume of 1.05 L (1000 mL + 50 mL). The volume percent concentration of hexane can be calculated as (volume of hexane / total volume) x 100. This gives (50 mL / 1050 mL) x 100 = 4.76% volume percent of hexane in the solution.
What is the volume percent concentration of hexadecimal in a solution made by mixing 50.0 ml of hexadecimal with 1.0 like of pentane?
To calculate the volume percent concentration of a component in a solution, you need to know the total volume of the solution. In this case, the total volume after mixing would be 50.0 ml + 1.0 ml = 51.0 ml. To find the volume percent of hexadecimal, you would take the volume of hexadecimal (50.0 ml) divided by the total volume of the solution (51.0 ml) and multiply by 100. This gives you a volume percent concentration of hexadecimal in the solution.
What term is used to describe the mixing of copper sulphate and water?
The term used to describe the mixing of copper sulfate and water is "dissolving." When copper sulfate is added to water, it dissolves to form a homogeneous solution where the copper sulfate molecules are evenly distributed throughout the water.
Why is better to warm up the solution to 50 degrees Celsius before mixing?
Warming up the solution helps to increase the solubility of the substances, making it easier for them to dissolve. This can result in a more homogeneous mixture and better reaction kinetics. Additionally, heating the solution can help to reduce the viscosity and make the mixing process more efficient.
What is the pH of a solution made by mixing baking soda and water?
The pH of a solution made by mixing baking soda and water is around 8.5, which is slightly basic.
How many liters of a 90 percent acid solution must be mixed with a 15 percent acid solution to get 600 L of a 80 percent solution?
Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.
Is it possible to mix a 10 percent acid solution and a 40 percent acid solution to obtain a 60 percent acid solution?
No. The reulting concentration (percent) must be between the two components. So, with the two acids you are mixing, you cannot get an acid that is less than 10% or more than 40%
What is the volume percent concentration of hexane in a solution made by mixing 50.0 mL of hexane with 1.0 L of pentane?
To calculate the volume percent concentration of hexane in the solution, you need to determine the total volume of the solution first. Mixing 50.0 mL of hexane with 1.0 L of pentane gives a total volume of 1.05 L (1000 mL + 50 mL). The volume percent concentration of hexane can be calculated as (volume of hexane / total volume) x 100. This gives (50 mL / 1050 mL) x 100 = 4.76% volume percent of hexane in the solution.
What is the volume percent concentration of hexadecimal in a solution made by mixing 50.0 ml of hexadecimal with 1.0 like of pentane?
To calculate the volume percent concentration of a component in a solution, you need to know the total volume of the solution. In this case, the total volume after mixing would be 50.0 ml + 1.0 ml = 51.0 ml. To find the volume percent of hexadecimal, you would take the volume of hexadecimal (50.0 ml) divided by the total volume of the solution (51.0 ml) and multiply by 100. This gives you a volume percent concentration of hexadecimal in the solution.
How many ounces of the 50 percent alcohol solution should be mixed with the 1 percent alcohol solution to make 8 oz of the 20 percent alcohol solution?
Let x = ounces of 50% solution, and y = ounces of 1% solution. So that we have: 0.5x + 0.01y = 8(0.2) which is a linear equation in two variables, meaning there are infinitely many choices of mixing those solutions.
What term is used to describe the mixing of copper sulphate and water?
The term used to describe the mixing of copper sulfate and water is "dissolving." When copper sulfate is added to water, it dissolves to form a homogeneous solution where the copper sulfate molecules are evenly distributed throughout the water.
A chemist forms a solution by mixing 0.50 mol glucose and 2.0 kg water?
To create the solution, the chemist dissolves 0.50 moles of glucose in 2.0 kg of water. The molar mass of glucose (C₆H₁₂O₆) is approximately 180 g/mol, so 0.50 moles of glucose weighs about 90 grams. This results in a solution where the concentration of glucose can be calculated, and the total mass of the solution is approximately 2.0 kg of water plus 0.090 kg of glucose. Thus, the final mass of the solution is about 2.09 kg.
How many gallons of a 90 percent antifreeze solution must be mixed with 90 gallons of 15 percent antifreeze to get a mixture that is 80 percent antifreeze?
Let M equal the gallons of the 90% mixing solution. Let F equal the gallons of the final solution. So:90 + M = F.Also, the number of gallons of pure antifreeze in the final will equal the sum of the gallons of antifreeze in the two mixing parts:Original solution: ( 90 gal )*(0.15) = 13.5 gal [0.15 represents 15%]Mixing solution: M*0.90Final solution: F*0.80So 13.5 + M*0.90 = F*0.80Now you have 2 linear equations and 2 unknowns, you can solve for M & F, using your favorite method: M = 585 and F = 675. Add 585 gallons of the 90% to get 675 gallons of 80% solution.
Is mixing liquid soap and water a solution?
Yes, it is a solution.
Why is better to warm up the solution to 50 degrees Celsius before mixing?
Warming up the solution helps to increase the solubility of the substances, making it easier for them to dissolve. This can result in a more homogeneous mixture and better reaction kinetics. Additionally, heating the solution can help to reduce the viscosity and make the mixing process more efficient.
What is the pH of a solution made by mixing baking soda and water?
The pH of a solution made by mixing baking soda and water is around 8.5, which is slightly basic.
Chemist should wait 10-15 seconds after dispensing a volume of titrant before a reading is made. why is the wait a good laboratory technique?
Waiting 10-15 seconds allows for complete mixing of the titrant with the solution being titrated, ensuring an accurate and consistent reading. This helps minimize errors due to incomplete reaction or inadequate mixing.
