d=m/v
v= (4/3)(pi)(r^3)
set up equation for aluminum and lead
11.3*10^3=m/( (4/3)(pi)(ri^3))
2.7*10^3=m/( (4/3)(pi)(ra^3))
solve for m. then set two equations equal to each other, since they have the same masses. finally, solve your new equations for ra/ri
11.3*10^3( (4/3)(pi)(ri^3)) =m
2.7*10^3( (4/3)(pi)(ra^3)) =m
11.3*10^3( (4/3)(pi)(ri^3)) = 2.7*10^3( (4/3)(pi)(ra^3))
11.3*10^3/2.7*10^3 = (ra^3)/(ri^3)
(11.3*10^3/2.7*10^3)^(1/3)=ra/ri
Ratio ???? If you mean the formula, then aluminium chloride is 'AlCl3'. This formula tells that there are 3 atoms of chlorine and one atom of aluminium .
The ratio aluminium/oxigen is 0,66 in Al2O3..
Aluminium (Al) + Oxygen (O) = Aluminium Oxide (Al2O3)Aluminium Atomic weight = about 27Oxygen Atomic weight = about) 16Proportion in Al203 = Aluminium 54, Oxygen 48Thus the ratio of weight in Al2O3 is 54/48 = 1.125And the ratio present as reactants is 5.433/8.834 = 0.615Thus the Aluminium will run out before the Oxygen as the reaction proceeds, making the Aluminium the limiting reactant.
Aluminium has a high strength to wheight ratio
no
bidyogammes
a. 2 to 5.
Yes, if the side length of the cube is one-third of the radius of the sphere.
The area of a sphere is given by the formula A = 4πr² A sphere with radius r has an area = 4πr² A sphere with radius 2r has an area = 4π(2r)² = 4π.4r² = 16πr² The ratio of the larger sphere to the smaller = 16πr² : 4πr² = 4 : 1 If the area of the smaller sphere is 45 units then the area of the larger sphere is 45 x 4 = 180 units.
If they have the same radius then it is: 3 to 2
The ratio is 300 m2/500 m3 = 0.6 per meter.(Fascinating factoid: The sphere's radius is 5 m.)
The vertex of the cone would reach the very top of the sphere, so the height of the cone would be the same as the radius of the sphere. Therefore the ratio is 1:1, no calculation is necessary.
Volume of a sphere of radius r: V = 4pi/3 x r3 If the ratio of the radii of two spheres is 23,then the ratio of their volumes will be 233 = 1,2167
what z radius ratio
Surface area to volume ratio in nanoparticles have a significant effect on the nanoparticles properties. Firstly, nanoparticles have a relative larger surface area when compared to the same volume of the material. For example, let us consider a sphere of radius r: The surface area of the sphere will be 4πr2 The volume of the sphere = 4/3(πr3) Therefore the surface area to the volume ratio will be 4πr2/{4/3(πr3)} = 3/r It means that the surface area to volume ration increases with the decrease in radius of the sphere and vice versa.
This is hard to calculate precisely, due to the fact that Earth's density increases towards the center. However, you make a simplified calculation, by assuming a uniform density. Just calculate the ratio of the volume (and therefore, of mass) of a sphere which has half the radius of the Earth, and calculate the gravitational attraction (once again, you only need a ratio, compared to the complete Earth) on that object.
The surface area of a sphere with radius 'R' is 4(pi)R2 The volume of the same sphere is (4/3)(pi)R3 . Their ratio is (4 pi R2)/(4/3 pi R3) = (12 pi R2)/(4 pi R3) = 3/R