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For every molecule of octane burned, 8 molecules of carbon dioxide are produced in a balanced reaction for the complete combustion of octane.
octane + oxygen --> water + carbon dioxide
The balanced combustion reaction for octane would be: 2C8H18 + 25O2 → 16CO2 + 18H2O + heat
That grade of gasoline has too much octane.
Reaction of octane combustion- 2C8H18+25O2= 16CO2+ 18H2O That mean from 228g octane (16*22.4dm3) = 358.4dm3 of CO2 is produced. {because volume of each mole is 22.4dm3} Now, from 10 kg of octane produced volume of CO2 is = (358.4*10000)/228 =(15719.298 dm3/1000)m3 =15.719 m3.
octane bribine octane bribine
There is no octane in gasoline... it is the equivalent of octane.
For every molecule of octane burned, 8 molecules of carbon dioxide are produced in a balanced reaction for the complete combustion of octane.
octane + oxygen --> water + carbon dioxide
Heat and light (:
Burning octane is an exothermic reaction because it releases energy in the form of heat and light as it reacts with oxygen to form carbon dioxide and water.
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The balanced combustion reaction for octane would be: 2C8H18 + 25O2 → 16CO2 + 18H2O + heat
Became a break-dancer
Messaging> Settings (the left key) > Signature (#13)
The amount of catalyst left over after a reaction depends on various factors such as its reactivity, consumption in the reaction, and conditions. Without additional information, it is not possible to determine how much catalyst would be left over after using 10mL in a reaction.
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