aluminum hydrogen tellurate
Aluminium and Hydrogen
Aluminium reacts with dilute nitric acid to give aluminium nitrate and hydrogen gas. aluminium + nitric acid -> aluminium nitrate + hydrogen 2Al(s) + 6HNO3 (aq) -> 2Al(NO3)3 (aq) + 3H2(g)
As aluminium is a reactive metal, it will oxidise in air to form a hard coating of aluminium oxide which surrounds the metal. To observe the reaction of sulphuric acid and aluminium, this coating must first be specially removed. Effervescence will be observed, and hydrogen gas will be produced. aluminium + sulphuric acid (reacts to form) aluminium sulphate + hydrogen gas
Aluminium chloride
Yes. It reacts to give aluminium sulfate and hydrogen gas.
Mg(HTe)2
HTeO4- is the formula for hydrogen tellurate ion.
Sorry there is no such compound as aluminium hydrogen though there is aluminium hydride - AlH3 or if that isn't it aluminium hydroxide - Al(OH)3
aluminium+hydrochloric acid= aluminium chloride+hydrogen :)
Aluminium and Hydrogen
Aluminium reacts with dilute nitric acid to give aluminium nitrate and hydrogen gas. aluminium + nitric acid -> aluminium nitrate + hydrogen 2Al(s) + 6HNO3 (aq) -> 2Al(NO3)3 (aq) + 3H2(g)
Aluminium reacts with dilute nitric acid to give aluminium nitrate and hydrogen gas. aluminium + nitric acid -> aluminium nitrate + hydrogen 2Al(s) + 6HNO3 (aq) -> 2Al(NO3)3 (aq) + 3H2(g)
Yes,of course.As aluminium(Al)present above hydrogen(H) the reactivity series,it displaces hydrogen in hydrochloric(HCl) to form aluminium chloride(AlCl3) and as a result,hydrogen gas(H2) is evolved.
Aluminium oxide doesn't react with hydrogen.
As aluminium is a reactive metal, it will oxidise in air to form a hard coating of aluminium oxide which surrounds the metal. To observe the reaction of sulphuric acid and aluminium, this coating must first be specially removed. Effervescence will be observed, and hydrogen gas will be produced. aluminium + sulphuric acid (reacts to form) aluminium sulphate + hydrogen gas
Aluminium chloride
Yes. It reacts to give aluminium sulfate and hydrogen gas.