2.044 g AgCl / 143.33 g per mole = 0.01426 moles of AgCl
NaCl + AgNO3 --> AgCl + NaNO3
1 mole of AgCl = 1 mole of NaCl
The sample contained 0.01426 moles of NaCl
0.01426 moles NaCl x 58.44 g per mole = 0.8334 g NaCl
0.8334 / 0.8421 = 98.97% pure
I'm pretty sure this is the correct answer.
32%
32%
Crystallysation,solution,filtrate,solvent
To calculate it must be certain that the impurities do NOT react either with HCl or NaOH; hence they shouldn't be acidic or base compounds.
The concentration oh hydroxyl ions (OH)- is increased.
A sample of 0.3220 g of an ionic compound containing the bromide ion Br is dissolved in water and treated with an excess of AgNO3 If the mass of the AgBr precipitate that forms is 0.6964 g then bromide=0.3220g and AgBr precipitate=0.6964.
32%
32%
excess consumption of soft drinks may lead to excess stomach acid.Why? and how is this treated
acid
Crystallysation,solution,filtrate,solvent
A chemical sedimentary rock, such as rock salt or rock gypsum.
To calculate it must be certain that the impurities do NOT react either with HCl or NaOH; hence they shouldn't be acidic or base compounds.
50%
This is known as an evaporite, examples include Halite, Gypsum and certain types of Limestone.
The concentration oh hydroxyl ions (OH)- is increased.
Hydronium(H3O+) ions, which are formed when Hydrogen(H+) ions combine with water molecules.