Above 2000 degree centrgate.
The balanced chemical equation for the reaction is 2H2 + O2 -> 2H2O. Using stoichiometry, we find that 3g of H2 will react completely with 24g of O2 to form 18g of H2O. Therefore, the maximum amount of H2O formed when 3g of H2 reacts with 29g of O2 is 18g.
bromine water? The reaction between hexene, bromine, and water is an addition reaction.
Water breaking into its component elements would be a decomposition reaction.
The chemical equation for the gasification of coal can be represented as: C + H2O -> CO + H2
For the reaction 2 H2 + O2 -> 2 H2O, we see that 1 mole of O2 produces 2 moles of H2O. Therefore, to produce 10.2 moles of H2O, we would need 5.1 moles of O2.
= H2+O2 =2H2+O2=2H2O
No. It would have to be H2O2 - H2 = O2 in order to be balanced.
The reactants in this equation are hydrogen gas (H2) and oxygen gas (O2).
This simple equation is: 2H2 + O2 = 2H2O
It is not balanced. There should be a 2 in front of H2 and H2O
H2 +o2 --->h2o
H2 +o2 --->h2o
The balanced chemical equation for the reaction is 2H2 + O2 -> 2H2O. Using stoichiometry, we find that 3g of H2 will react completely with 24g of O2 to form 18g of H2O. Therefore, the maximum amount of H2O formed when 3g of H2 reacts with 29g of O2 is 18g.
bromine water? The reaction between hexene, bromine, and water is an addition reaction.
To form water (H2O) from hydrogen (H2) and oxygen (O2), the balanced chemical equation is 2 H2(g) + O2(g) → 2 H2O(g). From the equation, 2 volumes of H2 produce 2 volumes of H2O, meaning 1 volume of O2 produces 2 volumes of H2O. Therefore, to form 50 L of H2O, you would need 25 L of O2(g).
its doesnot seems practical but we can hypothetically say that, by dissociating H2O molecule to H2 and O2 by hydrolysis can act as fuel because h2 is combustable and O2 supports combution.
Water breaking into its component elements would be a decomposition reaction.