The ionization energy tells us about the energy required (and thus the ease) with which an atom/ion can give away an electron (in the outermost shell).
So, atoms with low ionization energies ( lowest for Caesium) give away the electron with ease
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Valence electron
Yes, it is correct.
The outer shell is called the valence shell
Cesium, or Cs, has 1 valence electron.
The outer energy level is in the electron cloud surrounding the nucleus. Each ring that surrounds the nucleus is an energy level and contains a different number of electrons.
magnesium has a 2 valence electrons. because the third electron is not a valence electron, or in the outer shell, much more energy would be needed to remove it
Ionization energy and electron affinity for cations and anions, respectively.
Valence electron
Valence electrons.
IONIZATION enthalpy is the amount of energy to lose electron from its outer most shell .
The Valence electron
Yes, it is correct.
The outer shell is called the valence shell
Briefly, it is the energy required to completely remove a valence (outer shell) electron from its atom when forming an ionic bond.See related links below for more info
The electrons on the outtermost energy level of an atom is called a valence electron.
This is called the ionization energy and an is different for each electron in the atom. Electrons in the outer shell (furthest from the nucleus) have the lowest ionization energy, electrons in the innermost shell (closest to the nucleus) have the highest ionization energy.
As each electron is removed, the successive ionization energy values increase. However, the ionization energy increases a lot when the sixth electron is removed. This suggests that the sixth electron is removed from a shell which is closer to the nucleus.