The easiest way to remember how to solve combustion reactions is to know that CO2 and H2O are always the two resulting products. Energy is the third and final product however for the purposes of this question it is not necessary. The other valuable piece of information is that other than your fuel source, C5H12, you will need O2 to manipulate your rich/lean ratio. To balance the equation first write out the the reactants and the products....C5H12 + O2 ----> CO2 + H2O and now balance by starting with Carbon on the left. Five on the left then five on the right. Next move to Hydrogen on the left, twelve on the left then 6 on the right. 6*2=12 total Hydrogens on the right. When you get to O2 you should just add up the total Oxygen on the right and divide by two and you will have your answer. 10+6=16/2=8 C5H12 + 8O2 ----> 5CO2 + 6H2O If you follow these steps you cannot logically fail.
To balance the equation SO2 + O2 -> SO3, you need to ensure the number of each type of atom is the same on both sides of the equation. Start by adding a coefficient of 1 in front of SO2 and O2, then balance the equation by adding a coefficient of 1 in front of SO3. This balances the equation as: 2SO2 + O2 -> 2SO3.
To balance the equation C + O2 → CO, you need to add a coefficient of 2 in front of CO. This balances the equation so that you have the same number of carbon and oxygen atoms on both sides: C + O2 → 2CO.
This equation is not balanced as given. To balance it, you need to change the coefficients of the reactants and products. The balanced equation is 4Al + 3O2 -> 2Al2O3.
The balanced chemical equation is 2HBr + H2 + Br2 + N2O → N2 + O2 + HBr + H2 + Br2. The equation provided in your question doesn't appear to balance correctly, so I attempted to balance it based on the chemical species presented. It's essential to ensure that the number of atoms of each element is the same on both sides of the equation.
Balanced Equation: 2Mg(NO3)2 = 2MgO + 4NO2 + O2
the answers is 6 _apex
This simple equation is: 2H2 + O2 = 2H2O
When it burns completely, each molecule of C4H8 becomes 4 molecules of CO2 and 4 molecules of H2O.
4P + 5O2 = 2P2O5
4Na + O2 --> 2Na2 + O
To balance the equation SO2 + O2 -> SO3, you need to ensure the number of each type of atom is the same on both sides of the equation. Start by adding a coefficient of 1 in front of SO2 and O2, then balance the equation by adding a coefficient of 1 in front of SO3. This balances the equation as: 2SO2 + O2 -> 2SO3.
2CO + O2 --> 2CO2
To balance the equation C + O2 → CO, you need to add a coefficient of 2 in front of CO. This balances the equation so that you have the same number of carbon and oxygen atoms on both sides: C + O2 → 2CO.
This equation is not balanced as given. To balance it, you need to change the coefficients of the reactants and products. The balanced equation is 4Al + 3O2 -> 2Al2O3.
The balanced equation is 4Sb + 5O2 → 2Sb2O5.
The balanced chemical equation is 2HBr + H2 + Br2 + N2O → N2 + O2 + HBr + H2 + Br2. The equation provided in your question doesn't appear to balance correctly, so I attempted to balance it based on the chemical species presented. It's essential to ensure that the number of atoms of each element is the same on both sides of the equation.
Balanced Equation: 2Mg(NO3)2 = 2MgO + 4NO2 + O2