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1. First of all there is a 1:1 molar ratio.

2. 1000g CaCO3

3. Mass divided Mol Wt = 10 mols (CaCO3 = 100 g/mol)

4. 10 mols CaCO3 produces 10 mols CO2

5. Ideal Gas Law is PV = nRT

P = Pressure = 1.03 ATM

V = Is what you are solving for

n = mols of CO2 = 10

R = Gas Law Constant (look it up either on the web or books in the units you are working with - ATM, celsius, liters OR convert them into something you do have)

6. Plug in the numbers and solve for V in liters - You're Done !

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Q: CaCO3 -- CO2 CaO how many liters of CO2 at 1.03 ATM and a temperature of 950 degrees celsius will be produced if there is 1.00 kg of CaCO3 and what are the calculations to solve it or formulas?
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