Iron chloride has a molar mass of 162 grams per mole. To find the number of moles, divide the mass of the sample by the molar mass.
FeCl3 ? 1.1 grams FeCl3 (1 mole FeCl3/162.2 grams) = 0.0068 moles of FeCl3 ------------------------------------
For this you need the atomic (molecular) mass of FeCl3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. FeCl3=162.4 grams .200 moles FeCl3
FeCl3 = 162.4 g/mole 1.1 grams ÷ 162.4 grams/mol = 0.0068 moles
.2M x V FeCl3=moles FeCl3 x 1mole Fe2S3/2mole FeCl3=moles of Fe2S3 x mm of Fe2S3/1 mole Fe2S3= g Fe2S3 x .65% yield. 2.75g Fe2S3/ .65= 4.23g Fe2S3/ 207.91= .02035 x 2mole FeCl3=.0407 moles FeCl3/ .2M FeCl3= .2035 L x 1000= 203.5 ml
This molarity is 0,0068 for the anhydrous salt.
Look up or calculate the molecular weight/molar mass of FeCl3. Then... 40.0 g FeCl3/MW FeCl3/0.275 L = M (concentration of FeCl3 in solution)
Iron (III) chloride has the molecular formula of FeCl3. Its molecular weight is 162.2 grams per mole. Concentration is moles of solute divided by volume of solution. Therefore, the answer is .224 moles per liter.
MOLARITY = number of moles/ volume in liters so if you have the volume along with the molarity you can calculate
Calculate the number of moles in 0.135 grams of HNO3?
No. of moles = Mass (grams) x Mr
54.54 moles
No, pure FeCl3 is not aqueous.