1.68
To find the number of moles of chloroform in 215 g, you need to divide the given mass by the molar mass of chloroform. The molar mass of chloroform (CHCl3) is approximately 119.38 g/mol. Therefore, 215 g of chloroform is equal to 1.80 moles.
To find the number of moles in 59.1 g of chloroform (CHCl3), you need to divide the given mass by the molar mass of chloroform. The molar mass of chloroform is approximately 119.38 g/mol. Dividing 59.1 g by 119.38 g/mol gives approximately 0.495 moles of chloroform.
To find the number of moles of chloroform, you first need to calculate the volume of chloroform at the given conditions using the ideal gas law. Once you have the volume, you can then use the formula n = PV/RT, where P is the pressure, V is the volume, R is the gas constant, and T is the temperature in Kelvin, to find the number of moles.
molar mass of CHCl3 is119.5gmol-1. so there are 0.49 moles.
To produce 1.5 moles of chloroform (CHCl3), you would need 3 moles of chlorine (Cl2) as the reaction is 1:1 between Cl2 and CHCl3. The molar mass of Cl2 is approximately 70.9 g/mol, so 3 moles of Cl2 would be 3 * 70.9 g. Therefore, you would need approximately 212.7 grams of Cl2.
To find the number of moles of chloroform in 215 g, you need to divide the given mass by the molar mass of chloroform. The molar mass of chloroform (CHCl3) is approximately 119.38 g/mol. Therefore, 215 g of chloroform is equal to 1.80 moles.
To find the number of moles in 59.1 g of chloroform (CHCl3), you need to divide the given mass by the molar mass of chloroform. The molar mass of chloroform is approximately 119.38 g/mol. Dividing 59.1 g by 119.38 g/mol gives approximately 0.495 moles of chloroform.
To find the number of moles of chloroform, you first need to calculate the volume of chloroform at the given conditions using the ideal gas law. Once you have the volume, you can then use the formula n = PV/RT, where P is the pressure, V is the volume, R is the gas constant, and T is the temperature in Kelvin, to find the number of moles.
molar mass of CHCl3 is119.5gmol-1. so there are 0.49 moles.
To produce 1.5 moles of chloroform (CHCl3), you would need 3 moles of chlorine (Cl2) as the reaction is 1:1 between Cl2 and CHCl3. The molar mass of Cl2 is approximately 70.9 g/mol, so 3 moles of Cl2 would be 3 * 70.9 g. Therefore, you would need approximately 212.7 grams of Cl2.
The formula of trichloromethane is CHCl3. The usual molar formulas of the three elements are C, H2, and Cl2. Based on these formulas, one mole of trichloromethane contains one mole of carbon, one-half mole of hydrogen, and one and one-half moles of chlorine.
(3.28 g of chloroform/.0275moles of chloro)= 119 g of chloroform. Just take the weights in grams and divide it by number of moles. Hope it helps!
To calculate moles from molarity, you use the formula: moles = molarity x volume (in liters). Simply multiply the molarity of the solution by the volume of the solution in liters to find the number of moles present in the solution.
2 moles.
To calculate the number of moles of oxygen in the reaction vessel, you need to know the amount of oxygen in grams and its molar mass. Then divide the mass of oxygen by its molar mass to obtain the number of moles. The formula to calculate the number of moles is: moles = mass / molar mass.
To produce 1 mole of chloroform, you need 3 moles of chlorine. So, to produce 1.5 moles of chloroform, you would need 4.5 moles of chlorine. Converting moles to grams by using the molar mass of chlorine (35.5 g/mol) gives you 160.5 grams of chlorine required.
To calculate the number of moles, first calculate the molar mass of boron (B), which is approximately 10.81 g/mol. Then use the Avogadro's number (6.022 x 10^23) to convert the number of atoms to moles. So, moles = number of atoms / Avogadro's number = 5.34 x 10^21 / 6.022 x 10^23 ≈ 0.089 moles of boron.