Calculate the pH of solution formed when 30cm3 of 0.125m naoh are reacted with 25cm3 of 0.15m hcl at 298k?

Answer 1

No. of mol of NaOH used = 30/1000 x 0.125 = 0.00375
No. of mol of HCl used = 25/1000 x 0.15 = 0.00375

No. of mol of HCl used = No. of mol of NaOH used.
Hence, the resultant solution will be neutral. pH ~ 7.
(NaCl formed is a neutral salt, does not undergo any form of salt hydrolysis)

Answer 2

To determine the pH of the solution formed when NaOH and HCl react, first calculate the moles of NaOH and HCl used in the reaction. Then identify the limiting reactant, which in this case is the one that is completely consumed first. Use the moles of the limiting reactant to determine the concentration of the remaining reactant in the solution. Finally, use this concentration to calculate the concentration of OH- or H+ ions in the solution and then convert it to pH using the formula pH = -log[H+].