Reverse the equation for the decomposition given since you are doing formation. This makes -5678 positive.
Lookup the enthalpy of formation of gaseous water and carbon dioxide and multiply them by their moles in the formation equation. Remember nitrogen is in base form, so it is 0. You want:
Delta H of Reaction = Sum of Prod - Sum of Reactants
5678 = X - [-2418 + 0 + -4722 ]
X = -1462
-1462/4 = -365.5
You shouldn't "calculate" a standard enthalpy of formation. The beauty of standard enthalpies of formation is that they are already calculated for you. That is why they are delineated by the term "standard" - they are standards that were figured out by chemists some time ago, that never change, and can be found in tables usually in textbooks and even on Wikipedia. If you need to know the standard enthalpy of formation of FeO, Google it. And let me know what you find...because I can't seem to find a set answer either. I have found one site that lists the standard enthalpy of formation of FeO to be 271.9 kJ/mol. But it hasn't been so evident in other places. No wonder you were confused! Good luck.
The standard enthalpy of formation for N2 gas is 0 kJ/mol.
The standard enthalpy of formation is the energy change when one mole of a compound is formed from its elements in their standard states. The standard enthalpy of reaction is the energy change for a reaction under standard conditions. The relationship between the two is that the standard enthalpy of reaction is the sum of the standard enthalpies of formation of the products minus the sum of the standard enthalpies of formation of the reactants.
To calculate the enthalpy of a reaction, you need to find the difference between the sum of the enthalpies of the products and the sum of the enthalpies of the reactants. This is known as the enthalpy change (H) of the reaction. The enthalpy change can be determined using Hess's Law or by using standard enthalpy of formation values.
The standard enthalpy for sodium sulphate is -1387kJ/mol.
To calculate the enthalpy of formation of Cl2NNF2(g), you can use the standard enthalpy of formation values of the reactants and products involved in the relevant chemical reaction. The enthalpy of formation is determined by the equation: ΔH_f° = ΣΔH_f°(products) - ΣΔH_f°(reactants). You need to find the standard enthalpy of formation for Cl2NNF2(g) and the standard enthalpies of the elements in their standard states (Cl2, N2, and F2) to perform this calculation. If the standard enthalpy values are not available, you may need to use Hess's law and related reactions to derive the value indirectly.
To calculate the enthalpy change of formation from combustion, you can use Hess's law, which states that the total enthalpy change for a reaction is the sum of the enthalpy changes for individual steps. First, determine the enthalpy change for the combustion reaction using a calorimeter or from standard enthalpy values. Then, apply the equation: ΔH_f = ΔH_combustion + Σ(ΔH_f of products) - Σ(ΔH_f of reactants), where ΔH_f is the standard enthalpy of formation. This allows you to derive the enthalpy of formation for the desired compound based on its combustion data.
You shouldn't "calculate" a standard enthalpy of formation. The beauty of standard enthalpies of formation is that they are already calculated for you. That is why they are delineated by the term "standard" - they are standards that were figured out by chemists some time ago, that never change, and can be found in tables usually in textbooks and even on Wikipedia. If you need to know the standard enthalpy of formation of FeO, Google it. And let me know what you find...because I can't seem to find a set answer either. I have found one site that lists the standard enthalpy of formation of FeO to be 271.9 kJ/mol. But it hasn't been so evident in other places. No wonder you were confused! Good luck.
The standard enthalpy of formation for N2 gas is 0 kJ/mol.
The standard enthalpy of formation is the energy change when one mole of a compound is formed from its elements in their standard states. The standard enthalpy of reaction is the energy change for a reaction under standard conditions. The relationship between the two is that the standard enthalpy of reaction is the sum of the standard enthalpies of formation of the products minus the sum of the standard enthalpies of formation of the reactants.
To calculate the enthalpy of a reaction, you need to find the difference between the sum of the enthalpies of the products and the sum of the enthalpies of the reactants. This is known as the enthalpy change (H) of the reaction. The enthalpy change can be determined using Hess's Law or by using standard enthalpy of formation values.
Oxygen gas (O2) does not have an enthalpy of formation because it is an element in its standard state, which has an enthalpy of formation of zero by definition. Ozone (O3), on the other hand, is a compound and has a defined enthalpy of formation because it is formed from its elements in their standard states.
The standard enthalpy for sodium sulphate is -1387kJ/mol.
The enthalpy of formation is defined as the change in enthalpy when one mole of a compound is formed from its constituent elements in their standard states. It is a measure of the energy released or absorbed during the formation of a substance. This value is crucial in thermodynamics and helps in predicting the feasibility of chemical reactions. The standard enthalpy of formation for elements in their standard states is defined as zero.
A standard formation reaction is the reaction of the ions which make up a compound in their standard states. For example, the standard formation reaction of H2SO4 is: 2H+(g) + SO42-(g) --> H2SO4 (l)
To calculate the change in enthalpy (H) for a reaction, you need to subtract the sum of the enthalpies of the reactants from the sum of the enthalpies of the products. This can be done using Hess's Law or by using standard enthalpy of formation values.
The standard enthalpy of formation of coconut oil is not a well-defined value as it is a complex mixture of triglycerides, which are composed of various fatty acids. The enthalpy of formation of each individual fatty acid can be determined, but not for coconut oil as a whole.