Purple permanganate ion is reduced and almost decolorized (to Mn(II)) by chloride ion in acid solution. Purple permanganate ion is reduced to green manganate ion by chloride ion in basic solution. In neutral chloride solution, there is no reaction.
Source: UW Card Catalog
Benzene decolorizes potassium permanganate because it is a reducing agent. Benzene can donate electrons to the permanganate ions, which causes the purple color of the permanganate solution to fade as it is reduced to colorless manganese ions.
Permanganate estimation is completed in acid solution because in acidic conditions, permanganate (MnO4-) is reduced to colorless manganous ion (Mn2+), allowing for the endpoint to be easily detected once all the substance being titrated has reacted. Additionally, the acid helps stabilize the permanganate solution and prevents premature oxidation.
When phenol reacts with potassium permanganate in an acidic medium, the purple permanganate solution turns colorless as it is reduced to manganese dioxide. This reaction is a redox reaction where phenol is oxidized to benzoquinone.
When zinc dust is added to an acidified solution of potassium permanganate, a redox reaction takes place. The zinc reduces the permanganate ion, MnO4-, to form colorless manganese ions, while itself getting oxidized to zinc ions. The overall result is that the purple color of the permanganate solution fades as it is reduced.
When Mohr's salt solution is added to potassium permanganate solution, a redox reaction occurs where permanganate is reduced to colorless manganese(II) ions. The pink color observed is due to the remaining manganese(VII) ions from the permanganate that form manganese(VII) ions with Mohr's salt.
permanganate ion is an oxidising agent and is reduced.
Benzene decolorizes potassium permanganate because it is a reducing agent. Benzene can donate electrons to the permanganate ions, which causes the purple color of the permanganate solution to fade as it is reduced to colorless manganese ions.
Permanganate estimation is completed in acid solution because in acidic conditions, permanganate (MnO4-) is reduced to colorless manganous ion (Mn2+), allowing for the endpoint to be easily detected once all the substance being titrated has reacted. Additionally, the acid helps stabilize the permanganate solution and prevents premature oxidation.
When phenol reacts with potassium permanganate in an acidic medium, the purple permanganate solution turns colorless as it is reduced to manganese dioxide. This reaction is a redox reaction where phenol is oxidized to benzoquinone.
Potassium permanganate and sulfite:2MnO4-(aq) + 5SO32-(aq) + 6H+(aq) --> 5SO42- + 2Mn2+(aq) + 3H2O(l)Note:Potassium and sodium ions do NOT react, they are tribune-ions
When zinc dust is added to an acidified solution of potassium permanganate, a redox reaction takes place. The zinc reduces the permanganate ion, MnO4-, to form colorless manganese ions, while itself getting oxidized to zinc ions. The overall result is that the purple color of the permanganate solution fades as it is reduced.
When Mohr's salt solution is added to potassium permanganate solution, a redox reaction occurs where permanganate is reduced to colorless manganese(II) ions. The pink color observed is due to the remaining manganese(VII) ions from the permanganate that form manganese(VII) ions with Mohr's salt.
When potassium permanganate solution is dropped into water, it dissolves and forms a purple solution. If concentrated sulfuric acid is then added, the manganese in potassium permanganate can be reduced to form a colorless compound. This reaction generates heat and can be exothermic. The resulting solution will likely be colorless or have a faint pink hue instead of the original purple color.
Permanganate titration should be done in an acidic solution because permanganate ion (MnO4-) is most stable in acidic conditions. In acidic solution, permanganate ion is reduced to manganese(II) ions (Mn2+) during the titration. This reaction helps in accurately determining the concentration of the substance being titrated.
When ethanol is mixed with potassium permanganate, the purple color of the potassium permanganate fades. This is because ethanol reduces the potassium permanganate to form manganese dioxide, which is a brown precipitate. As a result, the overall color of the solution changes from purple to brown.
If the potassium permanganate solution is prepared from stock solid potassium permanganate, it is important to remove manganese dioxide from the system. MnO2 catalytically decomposes permanganate into oxygen and lower ox. states manganese. Manganese dioxide is insoluble, whereas permanganate is very soluble. Boiling the solution would ensure that all solid permanganate had dissolved, and so little would be lost upon filtering out MnO2 (which remains insoluble at higher temperatures) The remaining solution will have a longer shelf-life due to the absence of the aforementioned decomposition catalyst. If the permanganate solution is required acidic, the use of a small amount of phosphoric acid can be effective. Typically, sulfuric acid is used in combination with permanganate as an acid oxidant. The problem being that sulfuric acid dissolves manganese and thus the catalyst becomes soluble, and difficult to remove. Stock acid solutions of permanganate have far reduced shelf-life. The addition of a small amount of phosphoric acid helps alleviate this. Manganese(ii) oxide reacts with acidified permanganate to form Manganese(iii) cations - these in turn precipitate from solution as manganese(iii)phosphate. Complex ions of manganese(iii) can also form with phosphate, and these partake roles in equilibrium resulting in their further deposition from solution. Once the phosphate complexes are removed by filtration of the hot acidified permanganate solution, the solution has a longer shelf-life.
In the reaction between chlorine and iodine ions, a redox reaction occurs where chlorine ions oxidize iodine ions to form diatomic iodine molecules. The chlorine ions are reduced to form chloride ions. This reaction can be represented as Cl2 + 2I- -> 2Cl- + I2.