Potassium permanganate (KMnO4) is purple, so I guess that "potassium manganate" is already purple!
When potassium manganate is mixed with water, it dissolves to form a purple solution. Over time, the solution may slowly turn colorless as the potassium manganate reacts with water and other substances present in the solution.
Because the end point can easily be observed. Example: consider the titration between potassium manganate (IV) which is purple and ammonium iron (II) sulfate - colourless. At the end point the colourless standard solution will turn pale pink when the correct volume of deep purple titre is added. No indicator is required. Also this is not necessarily an acid base rxn
When acidified potassium permanganate is added to an alkene, the purple color disappears due to the reduction of permanganate ions to colorless manganese dioxide. The alkene oxidizes the permanganate ions, causing them to be reduced and lose their color. This reaction is used to test for the presence of carbon-carbon double bonds in organic compounds.
The reaction between potassium iodide and potassium bromide in the presence of methylene blue will result in the formation of elemental iodine (I2) which imparts a purple color to the solution. Initially, the reaction mixture will be colorless, but as iodine forms, the solution will turn purple.
pH paper would go a deep purple in the presence of KOH (s) because it is a very strong alkali.
When potassium manganate is mixed with water, it dissolves to form a purple solution. Over time, the solution may slowly turn colorless as the potassium manganate reacts with water and other substances present in the solution.
Add KMnO4 (Potassium Permanganate) which is a purple solution. If it is added to an alkene or alkyne it will turn colourless and produces a brown precipitate.
It will turn purple
I'm not entirely sure but I'm pretty positive it turns black, thus releasing oxygen and this can be proved if the test tube containing the potassium manganate VII is connected to another test tube or bowl containig limewater because it will start to bubble and turn cloudy or milky.
Because the end point can easily be observed. Example: consider the titration between potassium manganate (IV) which is purple and ammonium iron (II) sulfate - colourless. At the end point the colourless standard solution will turn pale pink when the correct volume of deep purple titre is added. No indicator is required. Also this is not necessarily an acid base rxn
The element "Potassium" (K).
dark brown...or really dark purple
When acidified potassium permanganate is added to an alkene, the purple color disappears due to the reduction of permanganate ions to colorless manganese dioxide. The alkene oxidizes the permanganate ions, causing them to be reduced and lose their color. This reaction is used to test for the presence of carbon-carbon double bonds in organic compounds.
Potassium permanganate turns purple in water because it undergoes a reaction in the presence of water to form hydrated manganese dioxide, which is a purple compound. This change in color is due to the formation of the purple complex ion resulting from the reaction of potassium permanganate with water.
The reaction between potassium iodide and potassium bromide in the presence of methylene blue will result in the formation of elemental iodine (I2) which imparts a purple color to the solution. Initially, the reaction mixture will be colorless, but as iodine forms, the solution will turn purple.
If you add universal indicator solution to the water after the reaction with potassium, the indicator will change color depending on the pH of the solution. Potassium reacts with water to form potassium hydroxide, which is a strong base. The solution will likely turn purple or blue indicating a high pH.
For an acid, the solution remains colourless or unchanged. For an alkali, it would turn fuschia.