Na2O + H2O ---------> 2NaOH
Na2O(s) + H2O(l) = 2NaOH(aq) Like sodium metal , sodium oxide reacts with water, however, it does NOT liberate hydrogen, so there is no 'popping' or flashing flame. Na2O is a BASE NaOH is an ALKALI (Soluble Base)
To balance the reaction between NaOH and H2SO4, you first write out the unbalanced equation: NaOH + H2SO4 -> Na2SO4 + H2O. To balance it, you need to ensure the same number of atoms of each element on both sides of the equation by adjusting the coefficients. In this case, you would need to put a coefficient of 2 in front of NaOH to balance the equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
To balance the reaction between H3PO4 and NaOH, first write out the chemical equation: H3PO4 + 3 NaOH -> Na3PO4 + 3 H2O Now, each element must have the same number of atoms on both sides of the equation for it to be balanced. Adjust the coefficients in front of each compound to achieve this balance.
When sodium oxide (Na2O) reacts with water (H2O), it forms sodium hydroxide (NaOH), which is a strong base. The reaction between Na2O and H2O produces hydroxide ions (OH-) in solution, increasing the pH and making it basic.
2 NaOH + SO2 = H2O + Na2SO3
The reaction between sodium oxide (Na2O) and water (H2O) forms sodium hydroxide (NaOH). The chemical equation for this reaction is: Na2O + H2O -> 2NaOH
To determine the purity of a sample of caustic soda (sodium hydroxide, NaOH) containing 74.6% Na2O by weight, we need to consider the molar mass of Na2O and NaOH. The molar mass of Na2O is approximately 62.0 g/mol, and that of NaOH is about 40.0 g/mol. Since Na2O is made up of two sodium atoms, we can calculate the equivalent amount of NaOH: 74.6% Na2O corresponds to about 54.9% NaOH. Thus, the sample's purity in terms of NaOH is approximately 54.9%.
At very high temperature NaOH is decomposed and Na2O fumes are emited.The reaction is:2 NaOH = Na2O = H2O
my balance sheet does not balance why?
Na2O(s) + H2O(l) = 2NaOH(aq) Like sodium metal , sodium oxide reacts with water, however, it does NOT liberate hydrogen, so there is no 'popping' or flashing flame. Na2O is a BASE NaOH is an ALKALI (Soluble Base)
To balance the reaction between NaOH and H2SO4, you first write out the unbalanced equation: NaOH + H2SO4 -> Na2SO4 + H2O. To balance it, you need to ensure the same number of atoms of each element on both sides of the equation by adjusting the coefficients. In this case, you would need to put a coefficient of 2 in front of NaOH to balance the equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
To balance the reaction between H3PO4 and NaOH, first write out the chemical equation: H3PO4 + 3 NaOH -> Na3PO4 + 3 H2O Now, each element must have the same number of atoms on both sides of the equation for it to be balanced. Adjust the coefficients in front of each compound to achieve this balance.
To balance the equation between propionic acid (C3H6O2) and sodium hydroxide (NaOH), you need to form water (H2O) and sodium propionate (C3H5NaO2). The balanced equation is: C3H6O2 + NaOH -> H2O + C3H5NaO2. This equation is already balanced because there is an equal number of each type of atom on both sides of the equation.
When sodium oxide (Na2O) reacts with water (H2O), it forms sodium hydroxide (NaOH), which is a strong base. The reaction between Na2O and H2O produces hydroxide ions (OH-) in solution, increasing the pH and making it basic.
i dont know so help
2 NaOH + SO2 = H2O + Na2SO3
2Na + 2H2O -> H2 + 2NaOH