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What is the theoretical yield of aluminum oxide if 3.00 mol of aluminum metal is exposed to 2.55 mol of oxygen?
The balanced chemical equation for the reaction is 4Al + 3O2 -> 2Al2O3. Since the molar ratio between aluminum and oxygen is 4:3, aluminum is the limiting reagent. Therefore, the theoretical yield of aluminum oxide is based on the 3.00 mol of aluminum. Using stoichiometry, the theoretical yield of aluminum oxide would be 3.00 mol of Al * (2 mol Al2O3 / 4 mol Al) = 1.50 mol of Al2O3.
Is aluminum oxide (Al2O3) paramagnetic or diamagnetic?
Aluminum oxide (Al2O3) is diamagnetic.
What compound is formed when aluminum and oxygen combine?
Aluminum oxide is formed when aluminum and oxygen combine. This compound has the chemical formula Al2O3.
What is the theoretical yield of aluminum oxide if 3.60 mol of aluminum metal is exposed to 3.00 mol of oxygen Express your answer with the appropriate units.?
The balanced chemical equation for the reaction between aluminum and oxygen to form aluminum oxide is: 4 Al + 3 O2 -> 2 Al2O3. From the equation, 4 moles of Al react with 3 moles of O2 to produce 2 moles of Al2O3. Since there are 3.60 mol of Al (which is in excess) present and 3.00 mol of O2, 3.00 mol O2 will be the limiting reactant in this case. This will produce 2.00 mol of Al2O3. Therefore, the theoretical yield of aluminum oxide is 2.00 mol Al2O3.
Compound name for Al2O3?
This is an ionic compound with the name aluminum oxide.
What is the percent yield of this reaction if 750.0 g of aluminum oxide produced 256.734 g of aluminum?
Aluminum oxide, Al2O3 would produce aluminum by the following decomposition:2Al2O3 ==> 4Al + 3O2 750.0 g Al2O3 x 1 mole/101.96 g = 7.356 moles Al2O3 Theoretical yield of Al = 7.356 moles Al2O3 x 4 moles Al/2 mole Al2O3 = 14.71 moles Al Theoretical mass of Al = 14.71 moles Al x 26.98 g/mole = 396.9 g Al Percent yield = 256.734 g/396.9 g (x100%) = 64.68% yield (to 4 significant figures)
What is the theoretical yield of aluminum oxide if 3.00 mol of aluminum metal is exposed to 2.55 mol of oxygen?
The balanced chemical equation for the reaction is 4Al + 3O2 -> 2Al2O3. Since the molar ratio between aluminum and oxygen is 4:3, aluminum is the limiting reagent. Therefore, the theoretical yield of aluminum oxide is based on the 3.00 mol of aluminum. Using stoichiometry, the theoretical yield of aluminum oxide would be 3.00 mol of Al * (2 mol Al2O3 / 4 mol Al) = 1.50 mol of Al2O3.
What does Al2O3 plus H2SO4 yield?
When aluminum oxide (Al2O3) is added to sulfuric acid (H2SO4), it typically reacts to form aluminum sulfate (Al2(SO4)3) and water (H2O). This is a common reaction in which the sulfuric acid breaks down the aluminum oxide to form the aluminum sulfate salt.
What is the scinecetific word for al2o3?
Al2O3 is aluminum oxide.
How do you prepare 1000ppm Al solution from Al2O3?
To prepare a 1000 ppm aluminum (Al) solution from aluminum oxide (Al2O3), first calculate the amount of Al2O3 needed. Since Al2O3 contains about 53% aluminum by weight, dissolve 0.0186 grams of Al2O3 in enough water to make a final volume of 1 liter. This will yield a solution with a concentration of 1000 ppm Al. Finally, ensure thorough mixing to achieve a homogeneous solution.
Is aluminum oxide (Al2O3) paramagnetic or diamagnetic?
Aluminum oxide (Al2O3) is diamagnetic.
What is the theoretical yield of aluminum oxide if 3.40 of aluminum metal is exposed to 2.85 of oxygen?
To determine the theoretical yield of aluminum oxide, we first need to write and balance the chemical equation: 4 Al + 3 O2 -> 2 Al2O3. From the equation, we can see that 4 moles of Al reacts with 3 moles of O2 to produce 2 moles of Al2O3. Calculate the moles of Al and O2 provided, convert each to moles of Al2O3, and find the limiting reactant to determine the theoretical yield.
What is the chemical formulae of aluminum oxide?
We know that Al2O3 is the chemical formula for aluminum oxide.
What is the correct formula for aluminum oxide?
The chemical formula for aluminum oxide is Al2O3.
What is the chemical formula for aluminum oxide when heated?
Aluminum oxide is Al2O3 and when heated it is still Al2O3, so heating aluminum oxide does nothing to it.
What compound is formed when aluminum and oxygen combine?
Aluminum oxide is formed when aluminum and oxygen combine. This compound has the chemical formula Al2O3.
What is the theoretical yield of aluminum oxide if 3.60 mol of aluminum metal is exposed to 3.00 mol of oxygen Express your answer with the appropriate units.?
The balanced chemical equation for the reaction between aluminum and oxygen to form aluminum oxide is: 4 Al + 3 O2 -> 2 Al2O3. From the equation, 4 moles of Al react with 3 moles of O2 to produce 2 moles of Al2O3. Since there are 3.60 mol of Al (which is in excess) present and 3.00 mol of O2, 3.00 mol O2 will be the limiting reactant in this case. This will produce 2.00 mol of Al2O3. Therefore, the theoretical yield of aluminum oxide is 2.00 mol Al2O3.
