The electron configuration for carbon dioxide (CO2) is...
Oxygen 6 valence electrons, multiplied by 2 added to
Carob which has 4 valence electrons, totals to 16 divided by 2 makes the required bonds 8
: :O=C=O: : octet rule is observed. *Also* Carbon and Oxygen have an electronegativity difference bewteeen 0 and .5 so we know that a nonpolar bond is formed and that bond will have even distribution of electrons as is seen in the result.
1s2 2s2 2p2
[He] 2s2 2p2
The answer is carbon
1s2 2s2 2p2
If you mean 1s22s22p3, you would refer to the periodic table. Using 2p3, you would look at the second period (row), look at the p block, and count 3 elements to the right to find nitrogen.
Beryllium is located in group 2 of the periodic table and has a valency of two. It is an element in the 2nd period and has two main energy levels. Therefore the electron configuration is 1s2 2s2.
The long form electron configuration for carbon is simply 1s2 2s2 2p2. The noble gas shortcut electron configuration for C is [He] 2s2 2p2.
1S2 2S2 2P2 (electronic configuration of carbon)
[He] 2s2 2p2
The answer is carbon
1s2 2s2 2p2
Yes
The electronic configuration of carbon is 1s2 2s2 2p2, whereas its noble gas notation is [He] 2s2 2p2.
Carbon has the chemical symbol of C and an atomic number of 6. Its shorthand or electron configuration is 1s2 2s2 2p2.
If you mean 1s22s22p3, you would refer to the periodic table. Using 2p3, you would look at the second period (row), look at the p block, and count 3 elements to the right to find nitrogen.
1s^2 2s^2 2p^2
Beryllium is located in group 2 of the periodic table and has a valency of two. It is an element in the 2nd period and has two main energy levels. Therefore the electron configuration is 1s2 2s2.
Carbon is the sixth element with a total of 6 electrons. In writing the electron configuration for carbon the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for C goes in the 2s orbital. The remaining two electrons will go in the 2p orbital. Therefore the C electron configuration will be 1s2 2s2 2p2.