Cd^2+(aq) + 2Cl^-(aq) +2Na^+(aq) + S^2-(sq) ==> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)
The 2Na^+(aq) and the 2 Cl^-(aq) are spectator ions as they appear on both sides of the equation. Thus, the NET reaction is ...
Cd^2+(aq) + S^2-(aq) ==> CdS(s)
What else was your question. This is classed as a double replacement reaction.
It has been a long time, but I think it has to read: 2Na + 2H2O --> 2NaOH + H2 to be balanced.
The chemical equation is 2Na + H2SO4 --> Na2SO4 + H2
2Na + 2Fe(NO3)3 -> 6NaNO3 + 2Fe
Ba2+ + [2Cl- + 2Na+] + SO42---> BaSO4 + [2Cl- + 2Na+]Ba2++ SO42- --> BaSO4
2Na+ + CO32- + Sr2+ + 2Cl- --> SrCO3 + 2Na+ + 2Cl- Simplified: Sr2+ + CO32- --> SrCO3 (s)
2NH3 + 2NA = 3H2 + NA3N2
single replacment
H2. Hydrogen gas.
2NaH2 + O2 yields 2Na + 2H2O
2Na + 2H2O -> H2 + 2NaOH
It is an eothermic type of reaction.
2Na + 2H2O -------> 2NaOH + H2
The balanced equation for Na + HNO3 is: 2Na + 2HNO3 -> 2NaNO3 + H2
It has been a long time, but I think it has to read: 2Na + 2H2O --> 2NaOH + H2 to be balanced.
The chemical equation is 2Na + H2SO4 --> Na2SO4 + H2
2 or more
No. First Na is not a diatomic element so Na2 is not correct. Oxygen is a diatomic element so if it is by itself, there has to be a sibscript of 2. A balanced equation would be 2 Na plus O2---- 2(NaO) plus you cannot have a number in the middle of the product.