The oxidation number of Sb in Sb2O5 is +5.
The oxidation number of antimony (Sb) in Sb3O5 is +5. Oxygen typically has an oxidation number of -2, so by setting up an equation where the total oxidation numbers of the atoms equals the charge of the compound (0 in this case), we can determine the oxidation number of antimony in Sb3O5 to be +5.
In Sb₂O₄, oxygen is almost always assigned an oxidation number of -2. To find the oxidation number of Sb, you can set up the equation: 2x + 4(-2) = 0, where x is the oxidation number of Sb. By solving this equation, you'll find that the oxidation number of Sb in Sb₂O₄ is +5.
In K2MnF6, +1 for K, +4 for Mn and -1 for F In SbF5, +5 for Sb and -1 for F In KSbF6, +1 for K, +5 for Sb and -1 for F In MnF3, +3 for Mn and -1 for F In F2, 0 for F
The oxidation state of Sb in Sb2O4 is +4. As the oxygen has the oxidation state equal to -2, we have four oxygen atoms in total, so the negative charge is equal to -8. now to balance it we should have +8 charge as Sb2O4 is neutral. but we have two Sb atoms per molecule.so the each Sb atom has the charge equal to +4.
The balanced chemical equation for the reaction between nitric acid (HNO3) and antimony (Sb) is: 6 HNO3 + 2 Sb → 2 Sb(NO3)3 + 3 H2O
The oxidation number of antimony (Sb) in Sb3O5 is +5. Oxygen typically has an oxidation number of -2, so by setting up an equation where the total oxidation numbers of the atoms equals the charge of the compound (0 in this case), we can determine the oxidation number of antimony in Sb3O5 to be +5.
In Sb₂O₄, oxygen is almost always assigned an oxidation number of -2. To find the oxidation number of Sb, you can set up the equation: 2x + 4(-2) = 0, where x is the oxidation number of Sb. By solving this equation, you'll find that the oxidation number of Sb in Sb₂O₄ is +5.
In K2MnF6, +1 for K, +4 for Mn and -1 for F In SbF5, +5 for Sb and -1 for F In KSbF6, +1 for K, +5 for Sb and -1 for F In MnF3, +3 for Mn and -1 for F In F2, 0 for F
The balanced equation is 4Sb + 5O2 → 2Sb2O5.
The oxidation state of Sb in Sb2O4 is +4. As the oxygen has the oxidation state equal to -2, we have four oxygen atoms in total, so the negative charge is equal to -8. now to balance it we should have +8 charge as Sb2O4 is neutral. but we have two Sb atoms per molecule.so the each Sb atom has the charge equal to +4.
The balanced chemical equation for the reaction between nitric acid (HNO3) and antimony (Sb) is: 6 HNO3 + 2 Sb → 2 Sb(NO3)3 + 3 H2O
The element Sb is antimony. Its atomic number is 51, meaning it has 51 protons in its nucleus. The mass number of antimony can vary because it has several isotopes, but the most common isotope has a mass number of 121.
The sum of the oxidation states in H2SbO3 is equal to zero since the overall charge of the compound is neutral. In H2SbO3, antimony (Sb) has an oxidation state of +5, oxygen (O) has an oxidation state of -2, and hydrogen (H) has an oxidation state of +1. Summing these oxidation states gives an overall charge of zero.
SB means SpongeBob and 1 means season 1 and the 29next is the episode number, I think
theatomic number of Antimony (Sb) is 51 and its atomic weight is 121.760. Determine the following: # The number of neutrons # the number of valence eletrons # the type of elementtheatomic number of Antimony (Sb) is 51 and its atomic weight is 121.760. Determine the following: # The number of neutrons # the number of valence eletrons # the type of element
Sb (antimony)
Sb (antimony)