Yes. All light is a form of electromagnetic radiation, so this answer applies to all light spectroscopy.
No Gamma Rays do not have mass. All electromagnetic radiation has no mass.
Whenever the electron falls from an excited state to a lower level, energy is released in the form of electromagnetic radiation. The Electromagnetic radiation can be light of different wavelengths and therefore different colors
Energy of the photon = Planck's constant x frequency of the ultraviolet radiation E = h x f frequency of the ultraviolet radiation = speed of light / wavelength of the ultraviolet radiation f = c/ lambda E = 6.63 x 10-34 x 3 x 108 / 3 x 10-7 = 6.63 x 10-19 Joules
Colours are produced when electromagnetic radiation is emitted. The precise colour will depend on the wavelength of the radiation.
The 'B' doesn't actually stand for anything. It simply designates ultraviolet radiation of a certain range of wavelengths. Please see the link.
Ultraviolet Electromagnetic Radiation
It is spectroscopy.
Ultraviolet Radiation.
Molecules emit electromagnetic radiation in NMR spectroscopy.
No, it is a type of electromagnetic radiation, which ultraviolet is part of as well.
spectroscopy
Ultraviolet rays, or radiation, is a type of electromagnetic waves.
Spectroscopy
Spectroscopy is the scientific tool that is based on how atoms absorb and emit electromagnetic radiation. Spectroscopy deals with how an object's light is dispersed into its component colors or energies.
Ultraviolet radiation does that.
Jules Z. Klose has written: 'Radiometric standards in the vacuum ultraviolet' -- subject(s): Measurement, Radiation, Radiometry, Standards, Ultraviolet radiation, Vacuum ultraviolet spectroscopy
Both infrared and ultraviolet are kinds of electromagnetic radiation, as is the visible light.