You COULD... since theoretically the "R" value is a constant and so is arbitrary.. but to keep it simple.. use the kPa in the ideal gas law.. with R as 8.314
To convert kPa to atm, divide the pressure in kPa by 101.3 (since 1 atm = 101.3 kPa). Therefore, 15.20 kPa is equivalent to 0.150 atm when rounded to three decimal places.
Using the combined gas law (P1/T1 = P2/T2), we can calculate the pressure of the gas at the new temperature. Plugging in the values, we get P2 = (P1 * T2) / T1 = (400 kPa * 235 K) / 110 K = 853 kPa. Therefore, the pressure of the gas is 853 kPa when the temperature is raised to 235 degrees Kelvin.
To find the volume of the gas in the balloon, you can use the ideal gas law: PV = nRT. First, convert the temperature to Kelvin (21°C + 273 = 294 K). Then plug in the values: (101 kPa) * V = (0.26 mol) * (8.31 LkPa/(molK)) * (294 K). Solve for V to find the volume of the gas in the balloon.
To find the temperature, you can use the ideal gas law formula: PV = nRT. First, convert the volume to liters (275 mL = 0.275 L). Then plug in the values of pressure (175 kPa), volume (0.275 L), and number of moles (0.80 mol), and the gas constant (R = 8.314 J/mol*K) to solve for temperature (T).
Pressure of 23.8 in Hg to kPa is equivalent to 80596.0582 Pa (pascal)
1 kiloPascal is equal to 7.5006 mmHg. So, using that conversion rate, it can be found that 769.3 mmHg is equal to 102.6 kPa.
To convert kilopascals (kPa) to bar gauge (barg), subtract the atmospheric pressure (typically around 101.3 kPa) from the given pressure. In this case, 345 kPa - 101.3 kPa = 243.7 kPa absolute. Then, convert the absolute pressure to barg by dividing by 100, as 1 bar = 100 kPa. Therefore, 243.7 kPa / 100 = 2.437 barg.
To convert kPa to atm, divide the pressure in kPa by 101.3 (since 1 atm = 101.3 kPa). Therefore, 15.20 kPa is equivalent to 0.150 atm when rounded to three decimal places.
Using the combined gas law (P1/T1 = P2/T2), we can calculate the pressure of the gas at the new temperature. Plugging in the values, we get P2 = (P1 * T2) / T1 = (400 kPa * 235 K) / 110 K = 853 kPa. Therefore, the pressure of the gas is 853 kPa when the temperature is raised to 235 degrees Kelvin.
Pressure cannot be directly converted into temperature as they are different units of measurement. Pressure is typically measured in pascals (Pa) or kilopascals (kPa) whereas temperature is measured in degrees Celsius (°C). To convert pressure to temperature, you would need additional information such as the volume and the ideal gas law.
Conversion for kPa to mmHG: kPa x 7.501 = mmHg202.6 kPa x 7.501 = about 1,520 mmHg
To find the volume of the gas in the balloon, you can use the ideal gas law: PV = nRT. First, convert the temperature to Kelvin (21°C + 273 = 294 K). Then plug in the values: (101 kPa) * V = (0.26 mol) * (8.31 LkPa/(molK)) * (294 K). Solve for V to find the volume of the gas in the balloon.
When using the pressure formula. PV=nRT. Pressure(in ATM) x Volume(in liters)=n(number of moles) x R(gas constant=.0821) x Temperature(in kelvins)If you are given pressure in kpa you have to convert to ATM
To find the temperature, you can use the ideal gas law formula: PV = nRT. First, convert the volume to liters (275 mL = 0.275 L). Then plug in the values of pressure (175 kPa), volume (0.275 L), and number of moles (0.80 mol), and the gas constant (R = 8.314 J/mol*K) to solve for temperature (T).
ATM x 101.325 = kPa So, 2.5 x 101.325 = 253.312 kPa
The ideal gas constant has different values depending on the units one uses for pressure. Thus, if using atmospheres, R = 0.0821 L-atm/K-mole. If using kPa, R = 8.314 L-kPa/K-mole, and if using mm Hg, R = 62.36 L-mm Hg/K-mole.
More pressure means less volume. Calculate the ratio of pressure, then divide the 4.2 liters by that ratio.This assumes: * That the temperature doesn't change. * That the gas behaves like an ideal gas.