no
CH3OH has an H bond with an oxygen molecule, causing H bonding to be a force. It also has dipole-dipole interaction because it's a polar molecule. Thus, it has all three of the forces (including London dispersion).
The intermolecular forces in CH4 (methane) are London dispersion forces. Methane molecules are non-polar, so the only type of intermolecular force present is the weak temporary dipole-induced dipole interactions between molecules.
CHF3 is a polar molecule. The fluorine atoms are electronegative and draw electrons towards their end of the molecule, leaving the hydrogen with a slight positive charge on it. So dipole-dipole forces will act between the molecules. The molecules will also exert dispersion forces on each other, but these are much weaker than the dipole-dipole forces.
No, CH4 does not exhibit dipole-dipole attractions. It is a nonpolar molecule due to the symmetrical arrangement of its four hydrogen atoms around the central carbon atom, resulting in a net dipole moment of zero.
No it doesn't; as there is practically no difference in electronegativity between carbon and hydrogen to create a dipole.
CH3OH has an H bond with an oxygen molecule, causing H bonding to be a force. It also has dipole-dipole interaction because it's a polar molecule. Thus, it has all three of the forces (including London dispersion).
The intermolecular forces in CH4 (methane) are London dispersion forces. Methane molecules are non-polar, so the only type of intermolecular force present is the weak temporary dipole-induced dipole interactions between molecules.
CHF3 is a polar molecule. The fluorine atoms are electronegative and draw electrons towards their end of the molecule, leaving the hydrogen with a slight positive charge on it. So dipole-dipole forces will act between the molecules. The molecules will also exert dispersion forces on each other, but these are much weaker than the dipole-dipole forces.
Correct answers from Mastering Chemistry: NH3 - hydrogen bonding CH4 - Dispersion forces NF3 - dipole-dipole
No, CH4 does not exhibit dipole-dipole attractions. It is a nonpolar molecule due to the symmetrical arrangement of its four hydrogen atoms around the central carbon atom, resulting in a net dipole moment of zero.
Yes, methane (CH4) would exhibit van der Waals forces, specifically London dispersion forces. These forces arise from the temporary shifting of electron distributions, which induces a temporary dipole in neighboring molecules and leads to attraction between them.
No it doesn't; as there is practically no difference in electronegativity between carbon and hydrogen to create a dipole.
The pair of molecules with the strongest dipole-dipole interactions would be NH3-NH3 because ammonia (NH3) is a polar molecule with a significant dipole moment, leading to stronger attractions compared to the other options listed.
No, not all molecules exhibit dipole-dipole forces. Dipole-dipole forces occur between molecules that have permanent dipoles, meaning there is an uneven distribution of charge within the molecule. Molecules that are symmetrical and have a balanced distribution of charge, such as nonpolar molecules like methane, do not exhibit dipole-dipole forces.
The intermolecular forces in Cl2CO (phosgene) are primarily dipole-dipole interactions due to the polar nature of the molecule. Additionally, there may be weak dispersion forces between the molecules.
When molecules have permanent dipole moments
Dipole-dipole forces are stronger than dispersion forces (Van der Waals forces) but weaker than hydrogen bonding. They occur between polar molecules with permanent dipoles and contribute to the overall intermolecular forces between molecules.