it is possible in aq medium, the rean is like this
NH4OH + H2SO4 = (NH4)2SO4
The reaction between sulfuric acid and ammonia creates ammonium sulfate. H2SO4 + 2 NH3 = (NH4)2SO4
2NH3 + H2SO4 ===> (NH4)2SO4 Ammonium sulphate - fertilizers.
Sulfuric acid just adds a proton to ammonia to give ammonium: H+ + NH3 -> NH4+ or H2SO4 + NH3 -> NH4+ + HSO4-
Molecular equation: H2SO4 + 2NH3 ---> (NH4)2SO4 Complete ionic equation: 2H++ SO42- + 2NH3 ---> 2NH4+ + SO42- Net ionic: 2H+ + 2NH3 ---> 2NH4+
Ca(OH)2 -------- calcium hydroxide NH3 -------------- ammonia H2SO4 ----------- sulfuric acid CH3COOH ------- acetic acid HClO4 ------------ perchloric acid
h2so4
The reaction between sulfuric acid and ammonia creates ammonium sulfate. H2SO4 + 2 NH3 = (NH4)2SO4
There are several such molecules as H2O , NH3 , H2SO4 , SOCl2 etc.
There are several such molecules as H2O , NH3 , H2SO4 , SOCl2 etc.
2NH3 + H2SO4 ===> (NH4)2SO4 Ammonium sulphate - fertilizers.
Sulfuric acid just adds a proton to ammonia to give ammonium: H+ + NH3 -> NH4+ or H2SO4 + NH3 -> NH4+ + HSO4-
koh + h2so4-khso4 +h2o
Molecular equation: H2SO4 + 2NH3 ---> (NH4)2SO4 Complete ionic equation: 2H++ SO42- + 2NH3 ---> 2NH4+ + SO42- Net ionic: 2H+ + 2NH3 ---> 2NH4+
Yes. NH3, H2O, H2S, H2SO4; anything without carbon is an inorganic compound.
Ca(OH)2 -------- calcium hydroxide NH3 -------------- ammonia H2SO4 ----------- sulfuric acid CH3COOH ------- acetic acid HClO4 ------------ perchloric acid
To determine the moles of excess sulfuric acid left over after the reaction is complete, you need to compare the stoichiometry of the reactants. In this case, 2 moles of NH3 reacts with 1 mole of H2SO4. If you know the initial moles of NH3 and H2SO4 used in the reaction, you can calculate which one is in excess and how many moles of the excess reactant are left over.
Mix 120 g sulfuric acid with water to 1000 mL.